identify the data required & determine the volume of two compund solid bodies?

Question

1)how do i work out the volume?
do i work out the rectangle first then the semi circle?
http://s10.photobucket.com/albums/a121/TurboD15/?action=view¤t=DSC00515.jpg

2)do i split it into 2 rectangles, triangle & a circle?
http://s10.photobucket.com/albums/a121/TurboD15/?action=view¤t=DSC00517.jpg
if the template is 3mm think, what is the volume in cubic millimetres?

cheers all

http://i10.photobucket.com/albums/a121/TurboD15/DSC00517.jpg

area of circle 3.141 * 25 squared = 1963.125cm2

area of rectangles = Length * Width or Base * Height

220mm * 30mm = 6600mm2 or 66cm2

130mm * 30mm = 3900mm2 or 39cm2

area of triangle = 1/2 * base * height
1/2*130mm*125mm=8125mm2

how do i find out the volume in cubic millimetres if the template is 3mm thick?

Answer 1

First convert the units to the ones you want (mm) if thats what you are looking for.

For number 1 - Just add the volume of the sqare part to the half circle. It's basically just the area time 3m (300cm).

For number 2 - You can break it up however you feel, but yes 2 rectangles, a triangle and subtract the circle will work.

Just remember to use the correct units.

Answer 2

The easiest way would be to recognize that you have half of a cylinder and a rectangle.
The volume of the rectangle would be the length X width X height (make sure units are all consistent).

The volume of a full cylinder is pi X (radius)^2 X height, but you've only got half of it...

Answer 3

Your basic assumptions are correct.

This sort of 'complex shape' question is best handled by splitting the shape up into basic rectangles, triangles and circles (i.e. shapes that are easy to deal with) and then adding or subtracting the part results.

For the first you have a rectangular Bar (bottom part) 12 x 16 x 3m plus 'half a Rod' (top part) r8 x 3m.

Answer 4

Can you be more specific about the shape?
Is it a cylinder,a sphere, a semi sphere, a cuboid, a semi sphere on top of a rectangle?
Would be pleased to have a go at answer if shape and dimensions were known.