2007-01-16 07:57:16 · 25 answers · asked by K-E-G 4 in Family & Relationships ➔ Singles & Dating
And I thought I was way out there LOL *kisses to you beautiful*
You aren't thinking of doing away with yourself via Coca Cola are ya?! :)
2007-01-16 08:01:46 · answer #1 · answered by brazenone 3 · 1⤊ 0⤋
Well, Technially you can live a lot longer if you stop eating then if you stop taking in fluids. On avaergae you can survive about atwo months without eating. Because Coca-Cola is a liquid and it does hve carbohydrates and calories I would say a person can live 3 months tops.
2007-01-16 16:01:53 · answer #2 · answered by JessiBaby 2 · 0⤊ 0⤋
years
2007-01-16 16:06:27 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Starvation is fatal in 8-12 weeks. Eat a Sammich already Lindsey!
2007-01-16 16:02:21 · answer #4 · answered by mattymomostl 3 · 0⤊ 0⤋
not very long. You have to eat too. I don't think if it matters how much coca-cola you drink. it just matters how much food you eat.
2007-01-16 16:00:52 · answer #5 · answered by .:Feliciano:. 3 · 0⤊ 0⤋
Would that be before or after their stomach slowly and painfully got ate out from the acid in the coke?
2007-01-16 16:03:02 · answer #6 · answered by Kevin A 6 · 0⤊ 0⤋
A month or two. Since after a whole month of no food and all cocacola you'd start to crash. Since humans can last months just drinking water.
EDIt: plus, cocacola dehydrates you, so maybe a month.
2007-01-16 16:01:20 · answer #7 · answered by michael d 3 · 0⤊ 0⤋
Approximately 30 days.
The "rule of threes" tells us that you can go without air for approximately 3 minutes, water for approximately 3 days and food for approximately 30 days.
2007-01-16 16:00:24 · answer #8 · answered by Anonymous · 0⤊ 0⤋
Thats pretty much been my diet for 5 years.
I'm still here blood pressure spot on, weight average.
JUst don't forget to brush your teeth a lot.
2007-01-16 16:18:45 · answer #9 · answered by Bohdisatva 3 · 0⤊ 0⤋
Put down the fashion magazine and pick up a sandwich!
2007-01-16 16:00:38 · answer #10 · answered by dynamicduo79 2 · 0⤊ 0⤋