You are playing a game of craps, & you've just rolled the dice on your come-out roll........?

Question

and the dice total 5. You're a winner if you roll another 5 before you roll a 7. If you roll a 7 before you roll a 5, you lose. If you roll any other combination before you roll a 5 or a 7, you roll the dice again. With a come-out roll of 5, what are the chances that you will be a winner? You are using 2 normal dice with six faces on each, numbered 1 thru 6.

10 pts 4 the 1st correct ans.

No one has gotten the right ans yet, so I'm extending it for another day. Read the q again & try to figure it out. You may edit your ans if you wish. Tnx & Good luck!

Answer 1

The answer is 2/45. Your chances of winning are 2 out of 45.
After rolling the 5 on the first roll, your chances of rolling a 5 are 4/36 or 1 out of 9. Out of 36 possible combinations, a 5 can appear four times: 2+3, 3+2, 1+4, or 4+1. The chances of rolling a 7 are 6/36 or 1 out of 6. Out of 36 possible combinations, a 7 can appear six times in this manner: 1+6, 6+1, 2+5, 5+2, 3+4, or 4+3.
Since you can roll a 5 four ways and a 7 six ways, there are a total of 10 ways to roll a 5 or a 7. Four of those ten ways are winning rolls: 4/10 or 2/5. This has to be multiplied by the chances of rolling a 5 on your first roll, which is 1/9. So that 2/5.1/9=2/45.

Answer 2

Ok. The probability of rolling two dice which add up to 5 is 1/9 (4 pairs out of 36 possible), while the probability of rolling two dice which add up to 7 is 1/6 (6 pairs out of 36 possible). Let's say that the probability for everything else is P(A).

Since 1/9 + 1/6 + P(A) = 1, P(A) = 13/18.

You can win if you roll a 5 straight away, or if you roll anything else than a 7, and then roll a 5, and so on.

The probability of rolling a 5 (and winning) is:

1/9 + 1/9 * 13/18 + 1/9 * (13/18)^2 + ... =
= 1/9 * (1 + 13/18 + (13/18)^2 + ... )

Let's say that all which is in brackets equals S. So,

S = 1 + 13/18 + (13/18)^2 + ...
S = 1 + 13/18 * ( 1 + 13/18 + ... )
S - 1 = 13/18 * (1 + 13/18 + ... )
S - 1 = 13/18 * ( S - (13/18)^(n-1) )
S - 1 = 13/18 * S - (13/18)^n
S - 13/18 * S = 1 - (13/18)^n
5/18 * S = 1 - (13/18)^n

Assume n -> infinity.

5/18 * S = 1
S = 18/5

So, it's 1/9 times S,

1/9 * 18/5 = 2/5 = 0.4 = 40%

**** EDIT ****

Ok, if 5 is rolled the first time and then anything other than 5 or 7, then the first 5 is nullified. The odds of rolling a 5 become:

1/9 * 1/9 * 18/5 = 1/9 * 2/5 = 2/45 = 0.044 = 4.4%

Am I correct this time?

Answer 3

Craps gives you one of the best shots at making good on your money, provided you know which bets are the ones worth making and which ones to reconsider.

Craps is best played with patience. The Pass Line bet and the Place bet for 6 or 8 will stand you in good stead over the long haul. Because of the low house advantage, these are two of the best bets you're likely to make.

Pass Line Bets: you win if the shooter rolls a 7 or an 11 on the first roll, or if the shooter establishes a point by rolling 4,5,6,8,9 or 10 and then rolls that same number again before rolling a 7.

Place bet on 6 or 8: you win if either a 6 or an 8 (depending on what number you're betting on) is rolled before a 7.

Betting Any 7

You'll often find craps players betting on 'Any 7'. The odds of Any 7 bets pay out at 4 to 1. The chances of you actually landing that bet are 5 to 1. Do the math and you'll see that it's just not worth it.

Betting The Field

As tempting as it is to bet the field, because it gives you lots of numbers to win and the payouts can be fairly attractive, there are a few cautions. For starters, you lose money much faster on this bet, and for every 16 winning bets there will be 20 losing results. Numbers 6,7 and 8 come up most often and they won't win you any money on this bet. Nor do 5 and 9 (the fourth most frequent results).

Betting On The Centre - Table Propositions

They can carry a casino advantage as high as 16%.

Big 6 And Big 8

These bets pay only even money, despite the fact that they work much the same way as Place Win bets on 6 and 8. Go for the Place Bets instead - they pay 7/6 odds. To put it another way: the house edge on Place Bets for 6 and 8 is only 1.52%, while on Big 6 and Big 8 it's 9.1%.

Hardways

Beware the Hardways bet - they don't call it hard for nothing. A Hardways bet on 4 or 10 has odds of 7 to 1 and a house edge of 11.11%. Hardways bets on 6 or 8 are 9 to 1 with a house edge of 9.09%. There are easier bets to make.

Answer 4

the above answers are all correct

an easy way to remember is --- out of 36 combinations
6 ways to make 7
5 ways to make 6 or 8
4 ways to make 5 or 9
3 ways to make 4 or 10
2 ways to make 3 or 11
1 way to make 2 or 12

So since there are 6 ways to make a 7 and only 4 ways to make a 5, your chances are 3:2 against you making it ... which is why when you get paid "true odds" on your odds for the passline bet, you would get paid 3:2 on that bet
The odds are 3:2 against you making a 5 or 9 before a 7, they are 2:1 against you making a 4 or 10 before a 7 (there are 6 sevens and 3 4s or 10s so is is 6:3 or 2:1), and 6:5 against you making a 6 or an 8 before the 7

Since you do get paid true odds on the odds you take on the passline bet, it is the best bet in the casino. Almost all casinos offer double odd, but some offer more, as much as 5x and 10x odds. You should always take the maximum odds as it is an even odds bet and your best chance of winning in any game in the casino

Answer 5

The odds are 3:2 against you. The reasoning is simple. There are 6 ways to make a 7 (6-1, 1-6, 5-2, 2-5, 3-4, 4-3) and 4 ways to make a 5 (4-1, 1-4, 2-3, 3-2) the odds of winning are therefore 4/6 or 2/3. That's why you get 3:2 on any odds bets you place on your point.

Answer 6

Yep. Out of the 36 possibilities with the dice, 4 of them total a 5, making you a winner, and 6 of them total a 7, making you a loser. Disregard all the rest, because you just keep rolling. 4 chances to win: 6 chances to lose = 40% chance to win, which is the same as a 2:3 odds to win. Placing odds on these bets gets you a 3:2 payout, the inverse of your odds to win. The odds bets in craps are the only fair payouts in Vegas.

Answer 7

There are 36 combinations of the dice. The combinations of 5 are: 1-4,2-3,3-2,4-1. So the chances of winning on the next roll are 4 out of 36. The combinations of 7 are: 1-6,2-5,3-4,4-3,5-2,6-1. There are 6 ways to roll a 7. so you have a 6 out of 36 chance of losing. That leaves 26 out of 36 chances of rolling a different number.

Answer 8

You will win 40% of the time. or 2 out of 5 times.

Damn, what's with all these rocket science explanations. True odds pays 3-2. That means 3 losers and 2 winners out of 5 times.

Answer 9

Just a guess, 80%.

Answer 10

c.graves is correct