Hello
I have a 65W stepdown transformer (Input: 230/240 AC, Output 115V AC, 65VA (0.57A)). I live in Australia and it is 220Vs here.
I am aware of 'no-load losses' but I can't calculate roughly how much the transformer is consuming. If I leave this thing on all the time, would anyone be able to tell me how much excess power is being used?
Any equivalents? Would it be the same as leaving a light bulb on all the time? 2 light bulbs? Less? More?
Have I provided enough information? It would be great if anyone could.
2007-01-16 03:34:33 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
There's not enough info. You'll have resistive losses in the primary and you'll have core loses due to eddy currents. It all depends on construction.
2007-01-16 03:55:00 · answer #1 · answered by Gene 7 · 0⤊ 0⤋
Secondary voltage is 120/4 = 30 volts Current is E/R = 30/300 = 0.1 amp Power is E•I = 30x0.1 = 3 watts in the load there is no power dissipated in the winding, for an ideal transformer, and you don't have enough info to calculate the actual power Primary power is also 3 watts for an ideal transformer, but again, this is NOT dissipated in the winding. that is the total power dissipated by the transformer and load. current is 3/120 = 25 mA
2016-05-25 00:03:20 · answer #2 · answered by Anonymous · 0⤊ 0⤋
No load loss is considered as negligible if not loaded .
transformers do consume on copper when they are loaded
no load is stray losses, you can leave it with out loading it may not consume more than as little as 5 watts or one or two percent of 65 watts
2007-01-16 03:40:30 · answer #3 · answered by david j 5 · 0⤊ 0⤋