Consider all the five digit numbers formed by using the digits 1,2,3,4 and 5 once and only once in each number formed. What is the sum of all of these five digit numbers?
2007-01-16 01:14:00 · 8 answers · asked by christiechritter 2 in Entertainment & Music ➔ Jokes & Riddles
1800 - ok no i read the question wrong
ok now i get 3,999,960 does that sound right
this is my idea - each number is at each position 24 times (i.e. there are 24 numbers of 5XXXX and XXX2X etc etc)
therefore if you take 24 times each number (or 1+2+3+4+5) times its power of ten
Then add then all together to get the answer
Is this wrong?
2007-01-16 02:16:54 · answer #1 · answered by tor 4 · 2⤊ 0⤋
The number of different 5 digit numbers so formed must be 5! = 120
The average of these numbers, by symmetry, must be 33333
So the sum must be 120 * 33333 = 3999960
2014-04-25 11:34:38 · answer #2 · answered by Anonymous · 1⤊ 0⤋
15
2007-01-16 01:25:55 · answer #3 · answered by Anonymous · 1⤊ 1⤋
No more than 9000 different numbers No less than 1000 different numbers
2016-03-29 00:01:18 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Thats not a good riddle.
2007-01-16 01:19:03 · answer #5 · answered by Kmart 2 · 0⤊ 2⤋
ide say 1800 hope im right!
2007-01-16 11:27:33 · answer #6 · answered by Anonymous · 0⤊ 1⤋
I don't get it
2007-01-16 01:19:58 · answer #7 · answered by LACANGEL9009 2 · 0⤊ 1⤋
1,481,400
2007-01-16 01:55:47 · answer #8 · answered by Maverick 6 · 0⤊ 1⤋