2007-01-15 23:51:40 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
There can be many a answers.For example you may buy19 roosters,1 hen and 6 chicks or 18 roosters3 hens and 3 chicks and so on.you should give another condition in your problem to get a definite answer
2007-01-16 02:17:24 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
300 Chicks
1 Hen & 297 Chicks
2 Hen & 294 Chicks
...
100 Hen & 0 Chicks
1 Rooster & 295 Chicks
2 Rooster & 290 Chicks
...
60 Rooster & 0 Chicks
1 Rooster & 1 Hen & 292 Chicks
1 Rooster & 2 Hen & 289 Chicks
...
2 Rooster & 1 Hen & 287 Chicks
2 Rooster & 2 Hen & 284 Chicks
...
58 Rooster & 1 Hen & 7 Chicks
58 Rooster & 2 Hen & 4 Chicks
58 Rooster & 3 Hen & 1 Chicks
59 Rooster & 1 Hen & 2 Chicks
2007-01-16 08:56:46 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I think it the answer is 58 chickens. Roosters, hens, and chicks are all chickens. So for a total of 9 coins, you can buy 5 chickens. You can buy 11 sets of 9 coins, so for 99 coins you get 55 chickens. With the remaining coin you can buy 3 more chicks. 58 total if you want equal distribution.
If you want to maximize your purchase, just buy 300 chicks for 100 coins.
2007-01-16 08:06:03 · answer #3 · answered by ogdensburgrivertrash 1 · 0⤊ 0⤋
300
2007-01-16 07:59:09 · answer #4 · answered by oldmanwitastick 5 · 0⤊ 0⤋
300 chickens can be broght and this can be found by 100*3
2007-01-16 08:09:38 · answer #5 · answered by kritika 2 · 0⤊ 0⤋