If a+b+c =0
Show that 1/a+1/b+1/c = 0 (progressions)
2007-01-15 19:37:50 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
This is not generally true.
For example let
(a,b,c) = (1,2,-3)
Then
a + b + c = 1 + 2 - 3 = 0
1/a + 1/b + 1/c = 1/1 + 1/2 - 1/3 = 7/6 ≠ 0
2007-01-15 21:40:59 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋
if 1+2+-3=0, then 1/1+1/2+1/-# IS not 0.however, 0 will be impossible because 1/0= infinity. thus, there is something like a fraction inside.
2007-01-16 03:44:00 · answer #2 · answered by WShuo 1 · 0⤊ 0⤋
a = 0, b = 0, c = 0.
2007-01-16 03:40:54 · answer #3 · answered by Anonymous · 0⤊ 0⤋
1/a + 1/b + 1/c = 0
hence: bc/abc + ac/abc + ab/abc = 0
i.e.: a = 3 b = 3 c = 3
then: 9/27 + 9/27 + 9/27 = 0
27/27 = 0
therefore: 27=27
2007-01-16 04:37:59 · answer #4 · answered by eskimo 1 · 0⤊ 0⤋
i dont think it does because you'd have 1/0 in teh second problem unless you give abc specific numbers...
2007-01-16 03:42:40 · answer #5 · answered by Anonymous · 0⤊ 0⤋