2007-01-15 17:34:30 · 3 answers · asked by Sush517 2 in Science & Mathematics ➔ Mathematics
5000 lb x 231 ft / 120 sec = 9625 ft-lbs per sec x 1 horsepower/550 ft-lbs per sec = 17.5 horsepower
(This assumes that you mean 5000 pounds of force/weight, not 5000 pounds of mass.)
2007-01-15 17:40:19 · answer #1 · answered by Jim Burnell 6 · 0⤊ 0⤋
It takes 17.5 horsepower.
_____________________________________________________
1 horsepower is equal to 33,000 foot-pounds per minute.
Lifting 5000 pounds to a height of 231 feet in 1 minute requires 5000*231 = 1,155,000 foot-pounds of force
Since it will take 2 minutes, it will only require 1155000/2 = 577500 foot-pounds
577500/33000 = 17.5 horsepower
2007-01-16 01:40:10 · answer #2 · answered by gamefreak 3 · 0⤊ 1⤋
500 lb(force)*1hp/(550ft-lbf)
*231ft/120sec=17.5hp
This uses a conversion of 1 hp = 550 foot-pounds force
Curse you for making me remember that from Thermodynamics : )
2007-01-16 01:52:29 · answer #3 · answered by oneman c 2 · 0⤊ 0⤋