Solve: - a/4 >_16
A.) a_< -64
B.) a >_-4
C.) a>_-64
D.) a>_64
2007-01-15 17:23:59 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Solving (a/4) >= 16, yields a >= 64.
Solving (-a/4) >= 16, yields a <= -64.
2007-01-15 17:32:20 · answer #1 · answered by S. B. 6 · 1⤊ 0⤋
- a/4 >_16
So -a >64 or a<-64
Answer A.
2007-01-16 01:30:35 · answer #2 · answered by Anonymous · 0⤊ 0⤋
a<=-64
2007-01-16 01:28:18 · answer #3 · answered by raj 7 · 0⤊ 0⤋
if ">_" is ">=", then it's
D. a>=64 (multiply both parts by 4)
2007-01-16 01:27:53 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I get A
2007-01-16 01:27:39 · answer #5 · answered by kellenraid 6 · 0⤊ 0⤋
-a/4 ⥠16
-a ⥠64
a ⤠-64
A
2007-01-16 01:27:43 · answer #6 · answered by Jim Burnell 6 · 0⤊ 0⤋
dont get your problem at all whats the underscore mean?
2007-01-16 01:28:47 · answer #7 · answered by theblueyoshi 2 · 0⤊ 0⤋
I get A too.
2007-01-16 01:38:32 · answer #8 · answered by crazy_tentacle 3 · 0⤊ 0⤋