Help me with this math problems plzzzz. U'll do a HUGE favor on me so plzzzzzzzzzz?

Question

1) MR. hills drives to work in Toronto,. ONe day his average speed going to work was 80km/h but returning it was 70km/h. If his total traveling time was 3 hours
how far from toronto is his home?

2) Six men can eat each a pizza in 2 mins. How long would it take all six men to eat one pizza?

3) My 5 brothers can each eat a whole roast chicken in 10 m ins. i can eat one in 8 mins. How long would it take all six of us to eat 2 chickens?

PLZZZZZZ tell me how u did. I get really confused by this problems..

aww u people are soo cute! Thanks a lot everyone!

Answer 1

1. distance = speed x time or
time = distance / time

*please be careful with the units all time check whther units are consistent. in you problem, speed is /hour and time also in hours,
so consistent.

In your problem it is obvious that time going to and back are not equal since speed going to and back are not equal. but the distance from work to home is always the same.

let t1 = time going to work
t2 = time returning
d = distance from home to work

t1 = d/80
t2 = d/70

*total travelling time is 3 hours, so"

t1 + t2 = 3 or
d/80 + d/70 = 3

* get LCD which is 560

7d / 560 + 8d / 560 = 3

multiply both sides with 560, you get

7d + 8d = 1680
15d = 1680
d = 112km



2. In problem two the trick is this in 2 minutes, 6 men can eat 6 pizzas. Therefore together,

2 min = 6 pizzas, or to know time/pizza, divide both sides by 6..

2/6 min = 6/6 pizzas
2/6 min = 1 pizza
1/3 min =1 pizza :)

***In algebra though, in doing work problems you have to think of the problem in terms of how much each person/whatever/whatever does in a given unit of time.***

Thus,

How much pizza does 1 man eat in a minute?
Its 1/2 / minute..

together 6 men can eat
6 x 1/2 pizza / minute

now let t be the number of minutes it takes for the 6men to eat 1 pizza together. so together they can eat 1/t pizza in a minute. putting into an equation,

1/2 + 1/2 + 1/2 + 1/2 + 1/2 + 1/2 = 1/t
6/2 = 1/t
3 = 1/t get the reciprocal to get t..

t = 1/3 min


3. Your brothers can eat ONE chicken in 10 minutes..
How much chicken in a minute..that is 1/10 chicken in a minute.
While you can eat 1/8 chicken in a minute.

Let t = time in minute all of you together can eat ONE chicken...
or 1/t of a chicken all of you can eat in 1 minute.

therfore,

1/10 + 1/10 + 1/10 + 1/10 + 1/10 + 1/8 = 1/t
5/ 10 + 1/8 = 1/t

reducing 5/10 to lowest term,

1/2 + 1/8 = 1/t
get the LCD which is 8..then,

4/8 + 1/8 = 1/t
5/8 = 1/t

get reciprocal,
t = 8/5 min to finish ONE chicken

So it takes 2t = 2 x 8/5 min to finish TWO chickens

Answer = 16/5 min

Answer 2

1, his average speed is 75 km per hour X 3 = 225 KM

2. pizza eaten in 120 seconds, divided by 6 = 20 seconds

3 5 brothers times 10 minutes = 50 minutes
other person 8 minutes plus 50 = 58 minutes

58 minutes for 6 chickens = 9 min and 2/3 minutes for one chicken

times 2 chickens
18 min and 4/3 min or 19 and 1/3 minute = 19 min 20 sec

There is also a riddle. 6 men can each eat a pizza in 2 minutes. How long does it take for one man to eat a pizza? 2 minutes

Answer 3

1) MR. hills drives to work in Toronto,. ONe day his average speed going to work was 80km/h but returning it was 70km/h. If his total traveling time was 3 hours
how far from toronto is his home?
x/80+x/70=3
70x+80x=5600*3
150x=5600*3
x=5600*3/150
=112 km

2) Six men can eat each a pizza in 2 mins. How long would it take all six men to eat one pizza?
1 man will take to eat i pizza=2 min
6 men will take=1/3 min


3) My 5 brothers can each eat a whole roast chicken in 10 m ins. i can eat one in 8 mins. How long would it take all six of us to eat 2 chickens?
my brother's time for i chicken=10 min
in1 min he will eat 1/10 th
in 1 min 5 will eat=1/2
my time for 1 chicken=1/8
in1 min together=1/2+1/8=5/8
so the 6 willfinish in 8/5 min=1.6 min
or 1min and 36 sec
so the six will takefor two chickens=3minand 12 sec

Answer 4

This issue does not look to paintings. D for sure must be a million considering you're including a 5 digit quantity to a 4 digit quantity to get a 6 digit quantity. This additionally calls for c to be 9 and a to be 0. regrettably, then we run into themes with the tens and ones place. s+a million=r, yet s+0+(a in all danger carried a million) = e. There at the instant are no values which you will put in that permit each letter to have a different fee and yet sparkling up the priority. If area of expertise isn't needed, you would be able to desire to have: 0=a a million=d 2=n 3=none 4=o 5=s,e 6=r 7=none 8=g 9=c

Answer 5

Number 1:

This is basically a D=RT problem.

You need to understand that distance both ways is the same. So if D=D, then RT=RT.

We know both rates, 80 and 70, so 80T=70T.

But the T's aren't the same since R was a different speed. So if together they add up to 3 hours, one can be x and the other must be 3-x.

So, 80(3-x) = 70x .

Solve for x...

240-80x = 70x
240 = 150x
x = 1.6

Substitute back into the equation, and 70x = 112 and 80(3-1.6) = 112 ..........

So it's 112 miles to his home!!!!

Hopefully 2 & 3 come from someone else.

Answer 6

x = distance to toronto
travel time to work = x/80
travel time from work = x/70

equation - total time
x/80+x/70 = 3
x/8+x/7 = 30
(7x+8x)/56=30
15x=30*56
x=30*56/15=2*56 = 112

2. 2/6 = 1/3 minute= 20 seconds

3. 2/( 5*1/10 + 1/8) = 2 / (1/2 + 1/8) =
= 2 *8/ (4+1) = 16/5 = 3+1/5 minutes = 3:12

Answer 7

1) assume distance is D and required time from home to work is T,
we get time required from work to home is (3-T)
>> D=80*T
D=70*(3-T)
>> 80*T = 70*(3-T) >> 80*T = 210 -70*T >> T=210/150=1.4 hrs

>> D= 80 * 1.4 == 112 km


2) six men can eat each a pizza in 2 mins >>
six men can eat each (1/6) pizza in (2/6) mins >>
six men can eat one pizza in 2/6 mins ..20seconds

Answer 8

1. Distant/80 + Distant/70 = 3, D = 112km
2. 2/6 = 1/3 m
3. 10+8 = 18m

Answer 9

i am not sure >>

2) 6/2 = 3

Answer 10

1. t1+t2=3h
V1t1=V2t2 (it better since the distance is the same each way)

t1=3-t2
V1(3-t2)=V2t2

t2=3V1/(v2+V1)=
t2=3(80)/(80+70)=
t2=1.6 h
t1=3-1.6=1.4h
D=V1t1=80 (1.4)=112 km