80.000 g of a hydrate lost 14.698 g on heating. The anhydrous salt contains 21.800 g calcium, 0.548 g hydrogen, 18.847 g phosphorus, the rest being oxygen. What is the simplest formula of the hydrate?
2007-01-15 16:32:08 · 3 answers · asked by Meno 1 in Science & Mathematics ➔ Chemistry
I think you have only 16.847 g phosphorus and the simplest formula becomes :
Ca2 H2 (PO3)2 . (H2O)3
See details here:
http://answers.yahoo.com/question/index;_ylt=An.D2TeTiTyvtEI.2meDGcLsy6IX?qid=20070115094055AAvLB7t
2007-01-16 00:00:08 · answer #1 · answered by cordefr 7 · 0⤊ 0⤋
The mass lost is completely water. Use this alongside with the relative atomic mass of water (18 g/mol) to discover the range of water atoms in a unmarried mole of hydrate. round to the nearest integer if mandatory
2016-11-24 20:35:02 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Subtract 14.698g from the 80g to solve for oxygen (using other values, of course) and for the mass of the anhydrous compound.
The 14.698g needs to be changed to moles of water, as this is what evaporated upon heating.
Using the masses of Ca, H, P and O from problem and molar masses from periodic table, solve for moles of each.
Then divide largest number from smallest number to get multipier....
2007-01-15 18:40:45 · answer #3 · answered by teachbio 5 · 0⤊ 0⤋