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The measured pH= 5.18 for a solution containing 25.0mL 1.M NaCH3COO and 10 mL1.0 M CH3COOH. Calculate the corresponding value of Ka for the acetic acid.

2007-01-15 15:41:25 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Ka= [H+][A-]/[HA]

change pH to [H+] by using pH = -log [H+] and substitute for [H+] in equation

substitute the concentrations for base (NaCH3COO) and conjugated acid (HA = CH3COOH) and solve.

2007-01-15 16:22:13 · answer #1 · answered by teachbio 5 · 0 0

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