Can somone help me find the derivative?

Question

The equation is y = 5^ (x^2 + 2x) I need to find the derivative, please include the steps. Just in case...The eqaution is y equals 5 to the power of x squared plus 2x.

Answer 1

Using the formula (d/dx)[b^u]=[b^u] (ln b) {du/dx}
b standing for any constant
u standing for any function that is differentiable by x

y=5^(x^2+2x)

For application in this problem I allow
b=5
and
u=x^2+2x

y=5^(x^2+2x)

(d/dx)[b^u]=[b^u] (ln b) {du/dx}

dy/dx= [5^(x^2+2x)] (ln 5) {2x+2}

using the chain rule to remember the {du/dx} in the formula, this is standard "plug and chug." With the exception of getting the derivative of u. (which is where 2x+2 came from)

Hope this helps.
Still don't get it? Feel free to IM me.

Answer 2

Are you joking?

The answer is dy/dx= 10x =2 FOR ALL VALUES OF X