2x^2-5x+7=3 by completing the square
if it doesnt equal zero iam lost...help pls
2007-01-15 13:11:51 · 6 answers · asked by Zac 2 in Science & Mathematics ➔ Mathematics
2x^2-5x+7=3
2x^2-5x+4=0
x^2-5/2x+2=0
x^2-5/2x+?= -2+?
x^2-5/2x+((-5/2)/2))^2= -2+((-5/2)/2))^2
x^2-5/2x+25/16= -2+25/16
(x-5/4)^2= -7/16
x^2-5/4= ±√(-7/16)
x= ±√(-7/16)+5/4
x= (√(7)/4)i and -(√(7)/4)i
2007-01-15 13:22:05 · answer #1 · answered by 7 · 0⤊ 0⤋
2x^2-5x+7=3
<=> 2x^2 - 5x + 4 = 0
<=> 2(x^2 - 5/2 + 2) = 0
<=> (x - 5/4)^2 + 7 / 16 = 0
<=> (x - 5/4)^2 = -7/16
this equation has no real root
2007-01-15 13:23:25 · answer #2 · answered by James Chan 4 · 0⤊ 0⤋
subtract 3 from both sides
2x^2-5x+4=0
than
(2x-2)(x-2)
x = 1/2
and 2
2007-01-15 13:20:46 · answer #3 · answered by city 3 · 0⤊ 0⤋
2x²-5x+4 = 0
d = -5² - 4.2.4
d = 25 - 32
d = -7
2007-01-15 13:22:46 · answer #4 · answered by aeiou 7 · 0⤊ 0⤋
previously each little thing quite anybody might want to favor to properly universal the version between quick and quick medium bowlers quick = Who can bowl one hundred 40+ continuously quick-medium = Who can bowl 130 5+ continuously yet they can't pass one hundred 40+ each and each-time V.Aaron is short yet he can bowl one hundred 40+ with good line and length and also Albie morkel morne morkel's brother shorter yet besides the undeniable fact that bowls one hundred 40+ and that i save in recommendations Tim southee isn't lots tall both ! So is going for the no man or woman million bowler Dale steyn he's 5 feet 10 !
2016-11-24 20:17:25 · answer #5 · answered by Anonymous · 0⤊ 0⤋
2x^2-5x+4=0
x^2-2.5x+2=0
x^2-2.5x+1.5625=1.5625-2
(x-1.25)^2=-.4375
sq.root(x-1.25)^2=sq.root-.4375
x is a imaginary number
NO REAL ANSWER
2007-01-15 13:18:02 · answer #6 · answered by abcde12345 4 · 1⤊ 0⤋