Let's start with the case where it's one digit. In this case, all we have to do is solve for the equation
x^3 = x, and we get
x^3 - x = 0
x(x^2 - 1) = 0
x(x - 1)(x + 1) = 0
x = {1, -1, 0}
We discard x = -1 because we can't have -1 digits. We also can't have 0 because we can't have 0 digits in a number. Therefore, our answer is 1.
2007-01-15 13:23:51
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answer #1
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answered by Puggy 7
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1 or 0
2007-01-15 21:10:41
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answer #2
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answered by Anonymous
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0 and 1
2007-01-15 21:10:44
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answer #3
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answered by Anonymous
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You want numbers other than the trivial 0 and 1, I am sure...
There are four of them: 153, 370, 371, and I forget the last one.
* * * * *
OK, the last one is 407. These are known as the three-digit "narcissistic numbers" - the sum of the digits cubed equals the number. You can extend this to four-digit numbers, i.e. the sum of the digits raised to the 4th power equals the number; there are five naricissistic 4-digit numbers. The largest narcissistic number is 39 digits long - the sum of the digits raised to the 39th power equals the number.
Yes, I know that was w-a-y more than you cared to know about narcissistic numbers. :)
2007-01-15 21:12:19
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answer #4
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answered by Anonymous
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one!
2007-01-15 21:11:10
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answer #5
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answered by WaitingForAnswers 2
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