2007-01-15 12:40:50 · 18 answers · asked by Average Joe 2 in Entertainment & Music ➔ Polls & Surveys
What about now?
(x-1)^2+(y-2)^2+(z-3)^2=9
2007-01-15 12:45:51 · update #1
Now?
f(x) = ln [sqrt(9 - x^2) / (4 + x^2) ]
First things first, use the fact that
log[base b](a/c) = log[base b](a) - log[base b](c)
f(x) = ln [sqrt(9 - x^2)] - ln(4 + x^2)
Now, convert the square root as a power to 1/2.
f(x) = ln [ (9 - x^2)^(1/2) ] - ln(4 + x^2)
As per log property log[base b](a^c) = c * log[base b](a),
f(x) = (1/2) ln (9 - x^2) - ln(4 + x^2)
Now, let's take the derivative. Note that the derivative of ln(x) is 1/x, so that's what we're going to use, along with the chain rule. Also, keep in mind that the (1/2) can be ignored when taking the derivative.
f'(x) = (1/2) [ 1/(9 - x^2) ] (-2x) - [1/(4 + x^2)] (2x)
Simplifying, we have
f'(x) = -x/(9 - x^2) - 2x/(4 + x^2
2007-01-15 12:47:47 · update #2
no
but thanks for the 2 points
2007-01-15 13:00:05 · answer #1 · answered by Wheels 2 · 0⤊ 0⤋
Yes, you started boring me from the first.
.
2007-01-15 20:55:04 · answer #2 · answered by Freesumpin 7 · 0⤊ 0⤋
Nothing on answers could bore me!
2007-01-15 20:45:26 · answer #3 · answered by Bebe1016 6 · 0⤊ 0⤋
Not yet
2007-01-15 20:43:59 · answer #4 · answered by fordperfect5 7 · 0⤊ 0⤋
You haven't said anything yet, so no.
2007-01-15 20:44:18 · answer #5 · answered by oscpressgirl66 3 · 0⤊ 0⤋
I was already bored.
2007-01-15 20:47:32 · answer #6 · answered by SwoonWorthy 6 · 0⤊ 0⤋
just hook me up with them points
2007-01-15 20:46:45 · answer #7 · answered by chaingang325 2 · 0⤊ 0⤋
not yet...b/c i answered ur question
2007-01-15 20:44:03 · answer #8 · answered by ξℓ Çђαηφσ 7 · 0⤊ 0⤋
Not at all.
2007-01-15 20:46:32 · answer #9 · answered by Judas Rabbi 7 · 0⤊ 0⤋
no, average joe, u are not boring me..
2007-01-15 20:44:36 · answer #10 · answered by R O 3 · 0⤊ 0⤋
No
2007-01-15 20:44:13 · answer #11 · answered by Tink 5 · 0⤊ 0⤋