2007-01-15 11:41:31 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Use Avagadros number. 6.02x10^23
So your work should look like this
mol to n of part. = (DESIRED MOLES HERE) (6.02x10^23 / 1 mol) =Answer
2007-01-15 12:39:53 · answer #1 · answered by -Eugenious- 3 · 0⤊ 0⤋
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2016-05-16 12:07:41 · answer #2 · answered by ? 4 · 0⤊ 0⤋
that's a splash bigger than that! lol In a million mol of something, there are 6.02 x 10^23 debris. (Avagadro's consistent) So in 0.187, there are a million/0.187 = 5.35... situations much less ions than the consistent. So (6.02 x 10^23) / 5.35 is the kind of debris in 0.187 moles of Na+ ions. (it particularly is around a million.13 x 10^23)
2016-12-12 12:14:18 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Multiply by Avogadro's number, 6.02 E 23
2007-01-15 11:49:25 · answer #4 · answered by gebobs 6 · 0⤊ 0⤋
use avagadro's number...6.022x10^23 moles = 6.022x10^23 particles.
2007-01-15 11:45:56 · answer #5 · answered by Retarded Genius 4 · 0⤊ 0⤋
you use the conversion factor
6.022*10^23
2007-01-15 11:55:14 · answer #6 · answered by Sarah M 2 · 0⤊ 0⤋
I use a sledge hammer.
2007-01-15 11:45:50 · answer #7 · answered by Anonymous · 1⤊ 0⤋