Between 1992 and 1999, you added approximately 21 stamps per year to your collection. In 1997 you had 109 stamps.
Find an equation that represents the number of stamps in your collection, y, in terms of the year, t. Let t =0 correspond to 1992
2007-01-15 10:49:29 · 9 answers · asked by jeorge h 1 in Science & Mathematics ➔ Mathematics
y=21t {0
t=1, y=21
t=2, y=42
t=7 y=21*7=147 stamps
2007-01-15 10:57:17 · answer #1 · answered by ? 2 · 0⤊ 0⤋
Y=21t+(109)
take 1999-1992 and you get 7-1=6 so 6*21= 126+109=235
2007-01-15 19:09:58 · answer #2 · answered by shorty_rdb 2 · 0⤊ 0⤋
If you add 21 per year, that is 21*t.
Number of stamps=21(t - 5) + 109
=21t -105 + 109
= 21t + 4
Where t is the number of years since 1992
2007-01-15 18:58:18 · answer #3 · answered by keely_66 3 · 0⤊ 0⤋
y=~21(7t)
that means 7 years (between 1992 and 1999) times 21 stamps. Test it with 1997 y should be 109. So 21x5=105 which is fine as they said approximately... (wavy line means apporximately)
2007-01-15 19:08:35 · answer #4 · answered by matts_wife 2 · 0⤊ 0⤋
21 stamps per year is your slope. Thus your equation is y = 21t + 4
2007-01-15 18:57:41 · answer #5 · answered by daedgewood 4 · 0⤊ 0⤋
7x21= 147 stamps added in 7yrs between 92 and 99
2007-01-15 20:08:12 · answer #6 · answered by lou l 2 · 0⤊ 0⤋
^ seriously yall r just darn lazy to b askin all these ppl to do ur hw 4 u geez wadafux come of this world?!?
2007-01-15 18:58:10 · answer #7 · answered by Anonymous · 0⤊ 1⤋
do your own homework and quit cheating.
2007-01-15 18:58:21 · answer #8 · answered by Cabana C 4 · 0⤊ 0⤋
>.> Did your teacher die or something?
Apparently nobody can do homework anymore...
2007-01-15 18:55:21 · answer #9 · answered by dragon6xx 2 · 1⤊ 1⤋