Algebra Rational equations?

Question

First problem: z+4/6=3/2-2z+2/12 second problem: 5/-x-6=2/x third problem: 3a-2/2a+2=3/a-1 Does anyone know how to solve with correct answer? Help! No one is getting the right answer to these problems. Please help solve and show me how you did it....thanks ...You have all been helpful but answers are still coming up wrong...the answer to #1 is 2 The answer to#2 is -12/7 The answer to #3 is -1/3 , 4 Need to know how to solve these 3 problems

Answer 1

The reason people are getting the wrong answers is that you are not properly stating the problems. If you do not use paretheses toindicate exactly what the equation, it will be interpreted several different ways. I have tried to show the proper writing of the expression in order to get the answers you say are correct.

z+4/6=3/2-2z+2/12
(z+4)/6 = 3/2 - (2z +2)/12
2(z+4)/12 = 18/12 -(2z+2)/12 = (18 -2z-2)/12 = (16-2z)/12
2(z+4) = 16 -2z [denominators = so numerators =]
2z+8 =16 -2z
4z=8
z=2

5/-x-6 = 2/x
5/(-x-6) = 2/x
2(-x-6) = 5 x
-2x -12 =5x
-7x =12
x = -12/7

3a-2/2a+2=3/a-1
(3a-2)/(2a+2) = 3/(a-1)
(3a-2)(a-1) = 3(2a+2)
3a^2 -5a+2 = 6a + 6
3a^2-11a -4 = 0
(3a+1)(a-4) = 0
3a+1 = 0 --> a= -1/3
a-4 = 0 --> a = 4

I hope this shows you the importance of the use of parentheses in clarifying exactly what you mean.

Answer 2

The answer to number 1 is not 2. If you plug in 2 for z you won't have both the left and the right sides equal.

1) z + 4/6 = 3/2 -2z + 2/12
3z = 3/2 + 2/12 - 4/6
3z = 18/12 + 2/12 - 8/12
3z = 12/12 = 1
z = 1/3

* previous responder is right, if for example you have a z+4 as the numerator and 6 as the denominator you need to write:
(z+4)/6. Recheck the question and make sure you have copied it correctly.

Answer 3

wow i have no idea i got 1/4 for the first one r u sure your answers r right

Answer 4

Could you put some parentheses in so we can see what is actually in the denominator?