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First problem: z+4/6=3/2-2z+2/12 second problem: 5/-x-6=2/x third problem: x-3/x+1=x-6/x+5 fourth problem: 3a-2/2a+2=3/a-1 Does anyone know how to solve with correct answer? Help! No one is getting the right answer to these problems. Please help solve and show me how you did it....thanks

2007-01-15 09:39:27 · 2 answers · asked by gail 1 in Science & Mathematics Mathematics

2 answers

Ill answer one of them for you then you can figure out the rest

z + 4/6 = 3/2 -2z + 2/12 ----- multiply everything by 12 to get rid of the fractions

12z + 48/6 = 36/2 - 24z + 24/12 --- simplify
12z + 8 = 18 - 24z + 2 add 24 z to both sides
36z + 8 = 18 + 2 subtract 8 from both sides
36z = 18 + 2 - 8
36z = 12 -- divide both sides by 36
z = 12/36 = 1/3

z = 1/3

2007-01-15 09:46:57 · answer #1 · answered by Bill F 6 · 0 0

Please put in more spacing -- hard to read.

z+4/6 = 3/2 -2z + 2/12

Collect terms z's on one side, constants on another.

Add 2z to bot sizes, and subtract 4/6 from both sides

3z = 3/2 +2/12 -4/6

3z = 9/6 + 1/6 - 4/6 (equalizing terms)

3z = 6/6

3z = 1

z = 1/3

Use the same principle for the others.. move the constants to one side by subtracting the same amount from both sides.

2007-01-15 09:48:48 · answer #2 · answered by John T 6 · 0 0

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