Electric field in a cube?

Question

Hi,

A negative charge is contained by the cube in Figure Ex27.6 ( http://i137.photobucket.com/albums/q208/infinitbelt/p27-06.gif ), in which E1 = 13 N/C and E2 = 22 N/C. The electric field is constant over each face of the cube.

Does the missing electric field vector on the front face point in or out? -I got this as it points in.


Here's the question I am having trouble with:

What is the minimum possible field strength?

I thought that it should be 8 NC as that would give -1 NC in the cube. What am I doing wrong?


Thanks!

Any ideas?

Thanks!

Answer 1

Well one thing you might try to look at is the total x,y, and z field strengths. In the x direction (let's call the 10 and 20 fields as that dir), you have a total of 10 out and 20 in, for 10 in. In the y direction (let's let that be E1 and 10), you have 3 going in. And in the z direction (E2 and the field on the front face) you have 22 out and an unknown in, which you think is 8 N/C.

It seems to me that you must use pythagorean theorem with Ex, Ey, and Ez in 3 dimensions: Ex^2 + Ey^2 + Ez^2 = 0? In other words, the Ez must cancel the Ex and the Ey.

Just a first guess here.

Answer 2

costly, i think of of you have some mistake on your situation, as you have blended magnetic and electric powered fields in question. If question is nice, then we ought to choose to understand time fee of replace of one field to locate diverse field from it. So greater advantageous advice is severe to answer the respond actual lies in conventional Maxwell's equations. in case you already know them, freshen up them to freshen up your situation

Answer 3

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