helpppppp, please!
Explain, in terms of atomic structure, why the atomic radius of iodine is greater than the atomic radius of fluorine.
i have it at the tip of my tongue, but i don't know how to word it. help?
2007-01-15 09:14:07 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Fluroine is in the second row (or "period) of the periodic table. It has two energy levels for electrons to orbit. Iodine is in the fifth row, meaning it has five energy levels for electrons to orbit, making it that much larger.
In general, size increases as you move down the table because of the increased number of energy levels. Size decreases as you move right because of the higher number of protons, which causes the atom to hold its electrons tighter (they are more "electronegative").
2007-01-15 09:20:17 · answer #1 · answered by Intrepyd 5 · 2⤊ 0⤋
Iodine Atomic Structure
2016-12-31 03:46:37 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Atomic Radius Of Iodine
2016-11-07 09:45:56 · answer #3 · answered by ? 4 · 0⤊ 0⤋
thats like asking which comes first chicken or the egg
the answer is why does the chicken cross the road
2007-01-15 09:18:03 · answer #4 · answered by MiKe Drazen 4 · 2⤊ 1⤋
Why not use google and find your answers? They spell it out with diagrams too!
2007-01-15 09:17:44 · answer #5 · answered by ebay_convert 5 · 1⤊ 2⤋
Kid should'nt you be doing your own homework
2007-01-15 09:17:07 · answer #6 · answered by linlid m 1 · 0⤊ 2⤋
Ask you teacher
There job is to help studnts
2007-01-15 09:18:16 · answer #7 · answered by cloverlover531 2 · 0⤊ 3⤋