megan's mass is 28kg. she climbs the 4.8-m ladder of a slide and reaches a velocity of 3.2 m/s at the bottom of the slide. how much work was done by friction on meagan?
thats the question again - can anyone help me with this?
2007-01-15 08:40:27 · 3 answers · asked by Erica C 1 in Science & Mathematics ➔ Physics
pe = ke + friction
so the potential energy of megan at the top of the slide is = mgh
ke = 1/2 mv^2
the energy lost to friction is equal to the difference between potential and kinetic energy.
2007-01-15 08:55:20 · answer #1 · answered by bfleung18 2 · 0⤊ 0⤋
Conservation of Energry
All energy MUST be conserved and in this problem, it isnt. Some energy is lost due to work done by friction. Using mgh + work = 1/2mv^2 you can find that work.
The work done by friction is -1173.76 J. It is negative because friction was acting in the opposite direction of megan's movement.
2007-01-15 09:01:20 · answer #2 · answered by gansta 2 · 0⤊ 0⤋
According to my calculations 1173.76 Joules
Let me know if you need the full explation on this. I can write it up and email it to you via a pdf document.
2007-01-15 09:03:25 · answer #3 · answered by Phillip 3 · 0⤊ 0⤋