what is the prime factorization of 40
2007-01-15 07:23:37 · 9 answers · asked by zoka5538 2 in Science & Mathematics ➔ Mathematics
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2007-01-15 07:27:45 · answer #1 · answered by Dr Dave P 7 · 0⤊ 0⤋
360 is divisable by: 2, 3, 4, 5, 6, 9 & 10.
The prime factorization of 40 is: 5 x 8
2007-01-15 07:30:05 · answer #2 · answered by markos m 6 · 0⤊ 1⤋
360 is divisible by all of them!
As to prime factors: 360 = 2^3 x 3^2 x 5
The prime factors of 40 are 2^3 x 5
2007-01-15 07:32:56 · answer #3 · answered by Anonymous · 0⤊ 0⤋
360 is divisible by 2: 180; 3: 120; 4: 90; 5: 72; 6: 60; 9: 40; 10: 36.
40 breaks down to 4*10.. 10 breaks down to 5*2, while 4 breaks down to 2*2. Leaving: 2*2*2*5. Then put it how you need to finish the question.
2007-01-15 07:31:58 · answer #4 · answered by stormey4 2 · 0⤊ 0⤋
360 is divisible by all of them.
I assume you want divisibility rules used here:
It's divisible by 2 since it ends in 0.
It's divisible by 4, since its last 2 digits(60) is a multiple
of 4.
It's divisible by 10 and by 5 because it ends in 0.
It's divisible by 9(and therefore by 3) because
the sum of its digits is divisible by 9 and therefore
by 3.
Divide 40 by 2 you get 20
Divide 20 by 2 you get 10
Divide 10 by 2 you get 5, which is prime.
So 40 = 2*2*2*5 = 2³*5.
2007-01-15 07:33:33 · answer #5 · answered by steiner1745 7 · 0⤊ 0⤋
360 is divisible by all of them. Try punching them in on your calculator to prove it, you'll get whole numbers. It would be faster than typing all these questions.
40 can be factored like 5x2x2x2
2007-01-15 07:27:49 · answer #6 · answered by Intrepyd 5 · 0⤊ 0⤋
360 is divisible by all of them.
2007-01-15 07:27:39 · answer #7 · answered by Anonymous · 0⤊ 0⤋
1st question- all of them
2nd question- 2 to the 3rd x 5 (2x2x2x5)
2007-01-15 07:29:39 · answer #8 · answered by Catholic 14 5 · 0⤊ 0⤋
all of them
2007-01-15 07:27:56 · answer #9 · answered by strtat2 5 · 0⤊ 0⤋