My car has a 13.7 gallon tank. Assuming that gasoline is entirely made from octane(C8H18), how many POUNDS of CO2 would be froduced from my car each time I use a tank of gas? How many pounds of CO2 will produce from my car each year(I drive 21,500 miles each year)?
Some equalities you may find useful
- 1 lbs- 4536 kg
1 kg-2.205 lbs.
28.35g-3.785 liters
l inch-2.54 cm
density of octane-.855g/ml
my car averages 29.7 miles/gallon
use the following equation
C8H18 + 12 1/2 O2 --> 8 CO2 + 9H2O
if u can find the answer and show work, it would be greatly appreciated. Please hlp. thx It would be nice if u can show step by step using factor labeling or something
2007-01-15 07:01:13 · 2 answers · asked by coolphill517 1 in Science & Mathematics ➔ Chemistry
1st step: 114.26 g/mole of octane ((12.01*8)+(1.01*18))=114.26
2nd step: gallons to milliliters: 3785.41 milliliters per gallon
Therefore: 13.7 times 3785.41 equals 51,860 millileters per 13.7 gallons
3rd step: (.855 grams/ml)*(51,860 millileters) = 44340.4 grams
4th step: (44340 grams) * (1 mole/114.26g) = 388.07 moles of octane
5th step: (388.07 moles octane) * (44.01 g/moles CO2) * (8 moles CO2/ 1 mole octane) = 136631.69 g of CO2
6th step: (136631.69g) * ( 1kg / 1000 g ) = 136.63 kg
7th step: (136.63 kg) * (1 lb/ 4546 kg) = .03 lbs of CO2
8th step: (13.7 gallons) * (29.7 mi/ gallon) = 406.89 mi/ tank
9th step: (21,500 mi) * (tank/ 406.89 mi) = 52.8398 tanks/ year
10th step: 52.8398 times .03lbs of CO2 per tank = 1.58812 lbs/year
Final answer: 1.58812 lbs/year
I dunno if that's right, hope it helps though.
2007-01-15 07:25:31 · answer #1 · answered by calvinmaniac12 1 · 0⤊ 0⤋
I worked this out for you a few 10's of minutes back.
2007-01-15 07:06:15 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋