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A 35 kg mass is allowed to accelerate down a frictionless 15 degree ramp.
a) determine the value of the x-component of the force of gravity.
b) what is the acceleration of the block down the ramp?
d) how long will it take for the block to slide 40m?

2007-01-15 06:29:55 · 3 answers · asked by crazed1511 1 in Science & Mathematics Physics

3 answers

a) Zero, mass is moving in x direction cause of normal reaction of the ramp, and not the gravity.
b) acceleration = g cos15degrees
c) distance = (1/2) * a * (t^2)
that implies time = (square root of) ( 2 * distance / (g cos 15))

now use your calculators....

2007-01-15 06:41:51 · answer #1 · answered by Sandeep K 3 · 0 0

The force of gravity, vertical, can be resolved into two components: a component parallel to the ramp, which will accelerate the mass down it; and a component perpendicular to the ramp, which is ignored here because we are positing no friction. The parallel component will be m g sin(15), which can be used to compute the acceleration of the block and the distance traveled, using the customary formulas.

2007-01-15 14:40:13 · answer #2 · answered by Anonymous · 0 0

a) sin(35)*9.81

b) F=m*a

sin(35)*9.81*35=35*a
a= sin(35)*9.81

c)1/2*a*t^2=d
40=.5*sin(35)*9.81*t^2

3.77 seconds

j

2007-01-15 14:36:37 · answer #3 · answered by odu83 7 · 0 0

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