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show working out in number form plz

2007-01-15 06:28:08 · 13 answers · asked by Anonymous in Science & Mathematics Mathematics

13 answers

First: make the mixed fraction an improper fraction > multiply the whole number by the denominator and add the result to the numerator and place the new result over the original denominator...

2*2 = 4
4 + 1 = 5
> 5/2

(5/2) * (3/5)

Sec: multiply the numerators and denominators...

(5*3)/(2*5)

15/10

Third: simplify the fraction into lowest terms, if possible...

3/2

2007-01-15 07:51:27 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0 0

2 1/2 x 3/5=5/2 x 3/5.

numerator x numerator over denominator x denominator.

5 x 3=15.
2 x 5=10.

so the answer is 15/10, or 1 1/2.

2007-01-15 14:39:07 · answer #2 · answered by blah 3 · 1 0

change 2 1/2 into a fraction then multiply.
5/2 * 3/5

2007-01-15 14:33:51 · answer #3 · answered by w4gy 1 · 1 0

2 1/2 as a proper fraction is 5/2

so 5/2 x 3/5 is the qn

since we have 5 in the numerator and the denominator we can cancel them and we get 3/2

answer is 1.5

2007-01-15 15:25:41 · answer #4 · answered by srinsrinsri 2 · 1 0

2 1/2= 5/2 5/2x3/5=15/10 or 1 1/2. just multiply the numerators, and denominators together. formula is n x n/d x d=product

2007-01-15 14:39:45 · answer #5 · answered by lea.mosely21 2 · 1 0

=(5/2)(3/5)=3/2

2007-01-15 14:32:20 · answer #6 · answered by raj 7 · 1 0

2 and 1/2 equales to 5/2

so to do 5/2 multiplied by 3/5 you can just multiply top and bottom

5 x 3
-------
2 x 5

so 5 x 3 = 15
-------------------
and 2x5 = 10

So the answer would be 15/10

You simplify that and you get 1 and 1/2 :-D

2007-01-15 14:42:59 · answer #7 · answered by Anonymous · 1 0

2 1/2 * 3/5
= 5/2 * 3/5 [convert 2 1/2 into fractional form]
= 15/10 [mult of fractions is (num1*num2)/(denom1*denom2)]
= (3*5)/(2*5) [simplify common factor]
= 3/2 [remove common factor]
= 3/2 or 1.5

2007-01-15 14:40:15 · answer #8 · answered by willeykj 1 · 1 0

5/2 x 3/5
3/2

2007-01-15 14:30:15 · answer #9 · answered by      7 · 2 0

2.5 * 3 = 7.5 / 5 = 1.5

2007-01-15 14:33:23 · answer #10 · answered by Anonymous · 1 0

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