http://img.photobucket.com/albums/v213/kingwajuk/QUESTIONS.jpg
The question in on photobucket from a pass paper, how do u work the answer out :S
hey can u tell me why the answer is C, and what is the meaning of the following STA n, LDA n, LDA #n, STA #n, LDX n ?!
thxs
2007-01-15 03:26:22 · 4 answers · asked by wajid n 1 in Computers & Internet ➔ Computer Networking
LOSP data is transferred over the LOSP channel in 16-bit parcels. The data contains information used to control the HISP channel. The 16-bits of data are protected by 4 parity bits that are used to check the data for errors.
The data transfer rate of a LOSP channel is 6 Mbytes/s in each direction. The LOSP channel uses control signals that indicate when data is on the channel, when data is received, and when a transfer of data is finished.
When information transfers over the LOSP channel from the host system (or IOC) to the CRAY T3D system, the most significant bit of the first parcel transferred directs the information to the appropriate node. If this bit is 0, the information is for the output node. If this bit is 1, the information is for the input node.
When information transfers over the LOSP channel from the CRAY T3D system to the host system (or IOC), the input node and output node share the LOSP channel. The first node to request a transfer over the LOSP channel controls the channel until a disconnect is sent.
All clear now?
2007-01-15 03:48:14 · answer #1 · answered by Taffy Comp Geek 6 · 0⤊ 0⤋
STA LDA STX etc are all 6502 microprocessor assembler commands. Check out http://www.6502.org . Answer C is correct as it is showing the internal microcode of the 6502 uProc for the LDA #n assembler instruction.
2007-01-15 03:45:52 · answer #2 · answered by Del Piero 10 7 · 0⤊ 0⤋
Mr Mugabi say, you thicko student
2007-01-15 03:31:38 · answer #3 · answered by Anonymous · 0⤊ 1⤋
Jeez!! Looks complicated!! Good luck!!
2007-01-15 03:32:07 · answer #4 · answered by Fluke 5 · 0⤊ 0⤋