Factor completely. 6z3 – 27z2 + 12z?

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2007-01-15 03:10:25 · 6 answers · asked by Ryan A 1 in Education & Reference ➔ Homework Help

6z3-27z2+12z
3z(2z^2-9z+4)
(3z)(2z-1)(z-4)
z=0 1/2 4

2007-01-15 03:21:07 · answer #1 · answered by Lauren 2 · 0⤊ 0⤋

First: factor out 3z

3z(2z^2 - 9z +4)

Then factor the parenthetical:

3z(2z - 1)(z - 4)

And then you're done.

2007-01-15 03:17:30 · answer #2 · answered by Grover 3 · 0⤊ 0⤋

3z(z-4)(2z-1) is the lowest complete factors.

2007-01-15 04:02:09 · answer #3 · answered by august51944 2 · 0⤊ 0⤋

take a3 and a z out

3z(2z2-9z+4)

2007-01-15 03:15:42 · answer #4 · answered by Anonymous · 0⤊ 0⤋

3z (2z2-9z+4)

2007-01-15 03:14:04 · answer #5 · answered by K. C. 3 · 0⤊ 0⤋

zero

2007-01-15 03:13:56 · answer #6 · answered by Kodoku Josei 4 · 0⤊ 0⤋