Bill is $25
Waiter keeps $2
Each person gets back $1 ($1 X 3 persons = $3)
$25 + $2 + $3 = $30.
2007-01-15 03:18:12
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answer #1
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answered by JaneBond 3
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The $2 the waiter kept is part of the $9 they each spent. The other $3 are the dollars each received back from the waiter.
2007-01-15 03:15:49
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answer #2
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answered by Steve A 7
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Look from this prospective
each person bill was $ 8.3333337
3 x 8.3333337 = $ 25
since each gave $ 10 each for a total to $ 30
There was a $ 5 return
Divide 5 by 3
5 / 3 = $ 1.6666667
Each person would recieve $ 1.67 rounded to two decimal places.
- - - - - - - - - - -
The bill was 25 dollars
Each person gave $ 10
There was a $ 5.00 return
The waiter gave each person 1 dollar
The waiter kept 2 dollars
25 + 3 = 28
28 + 2 = 30
Everything is in order
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2007-01-15 03:54:30
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answer #3
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answered by SAMUEL D 7
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Yes the 3 friends paid 27 dollars, 25 went to the restaurant and 2 went to the waiter.
You sum 27+2 when actually you should subtract 2 from 27.
2007-01-15 03:16:36
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answer #4
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answered by catarthur 6
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It's only $25 not$30. 27 paid by the friends - 2 kept by the waiter = 25 in the cash register
2007-01-15 03:11:51
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answer #5
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answered by hayharbr 7
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so the friends spent $30 and each got $1 bac (total of $3)
$30 - $25= $5 (they should have gotten back $5) but they only got bac $3 ($5 - $3= $2) and the remaining $2 the waiter kept for himself! i hope this helps!!
2007-01-15 03:19:20
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answer #6
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answered by Anonymous
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So the bill is $25, and everyone gets a dollar back. so the amout paid for the bill is 25+2 for the tip.... every one gets a dollar back so 27 + 3 + 30
2007-01-15 03:20:04
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answer #7
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answered by Anonymous
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each paid $10
so, $10 x 3=$30
$30-$25 = $5----->balance of change
if each person gets $1 back and the waiter keeps $2, there will be no balance left..
2007-01-15 03:19:48
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answer #8
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answered by Oo T 3
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faulty accounting
cost to each =25/3 =8.33
tip 2/3 = .67
change 1.0
total $30.00
2007-01-15 03:23:05
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answer #9
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answered by CubicleWizard 2
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2016-10-07 04:46:21
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answer #10
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answered by ? 4
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