2007-01-15 03:04:58 · 8 answers · asked by Ryan A 1 in Science & Mathematics ➔ Mathematics
=3z(2z2-9z+4)
2007-01-15 03:11:34 · answer #1 · answered by srinu710 4 · 0⤊ 2⤋
6z3 – 27z2 + 12z
First notice that 3z is common to all 3 terms so factor it out:
3z(2z^2 -9z +4)
Now see if you can factor (2z^2 -9z+4). You can, getting:
3z(2z-1)(z-4)
2007-01-15 03:23:30 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
The roots of 10x² + 2x - 8 = 0 are x1 = -a million and x2 = 4/5 => 10x² + 2x - 8 = 10*(x+a million)*(x-4/5) = (x+a million)*(10x-8) ============ different possibilities are: 10x² + 2x - 8 = (2x+2)(5x-4) or 10x² + 2x - 8 = (5x+5)(2-8/5) and so on.
2016-10-31 04:05:00 · answer #3 · answered by Anonymous · 0⤊ 0⤋
First divide by the common factor, 3z
3z(2z^2 - 9z + 4)
Then do FOIL, starts like this you can fill in the rest:
3z(2z - .... )(z - .....)
2007-01-15 03:08:50 · answer #4 · answered by hayharbr 7 · 0⤊ 1⤋
Take 3z common.
3z(2z^2-9z+4)=0
So either z=0 or 2Z^2-9z+4=0
2z^2-8z-z+4=0
2z(z-4)-1(z-4)=0
(2z-1)(z-4)=0
so z=1/2 or z=4
So factors are z=0,z=1/2,z=4
2007-01-15 03:12:06 · answer #5 · answered by Tariq M 3 · 0⤊ 2⤋
3z(2z2-9z+4)
3z (z-4 )( 2z-1 )
2007-01-15 03:11:45 · answer #6 · answered by italianwiseass13 2 · 0⤊ 0⤋
factor out z
solve as quadradic
ans 0,0.5,4
2007-01-15 03:16:49 · answer #7 · answered by CubicleWizard 2 · 0⤊ 1⤋
3z(2z-1)(x-4)
2007-01-15 03:12:47 · answer #8 · answered by Steve A 7 · 0⤊ 1⤋