2007-01-15 02:02:37 · 13 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(3x+2)(2x+1)
2007-01-15 02:07:11 · answer #1 · answered by the_one_khmai 2 · 2⤊ 0⤋
Hi Tracey, are you serious about this question? Isn't it too trivial for wasting 5 precious points on??
Anyway, here we go:
For the first term 6x^2, find two factors such that their sum is less than the second term 7x. Let us try 3x and 2x and proceed as follows:
(3x + .... )(2x + .... )
Now find two factors such that their product is 2 and the product of each with 3x and 2x respectively add up to 7x.
(3x + 2)(2x + 1)
Note the positions of the 2 and 1. Reversing them would not yield the same thing.
2007-01-15 02:18:14 · answer #2 · answered by Paleologus 3 · 0⤊ 0⤋
= 6x2+4x+3x+2 = 2x(3x+2)+1(3x+2) = (3x+2)(2x+1)
the thing is to multiply the number with x2 and the last number without x i.e. 6*2=12 and then split the middle term such that the sum adds to 7 and the multiplcation gives 12 i.e. here 4 and 3 as 4*3=12 and 4+3=7
hope its clear now ^_^
2007-01-15 02:24:30 · answer #3 · answered by apocalypto 1 · 0⤊ 0⤋
Simplifying
6x2 + 7x + 2
Reorder the terms:
2 + 7x + 6x2
Factor a trinomial.
(2 + 3x)(1 + 2x)Final result:(2 + 3x)(1 + 2x)
2007-01-15 02:22:40 · answer #4 · answered by SHIBZ 2 · 0⤊ 0⤋
6x^2 + 7x +2
Find numbers whose sum is 7 and whose product is 6x2 = 12. The numbers are 3,4.
= 6x^2 + 3x + 4x +2
= 3x*(2x + 1) + 2(2x +1)
= (2x + 1) (3x+2)
2007-01-15 02:20:41 · answer #5 · answered by Pearlsawme 7 · 0⤊ 0⤋
i think this could be right, but im not sure:
6x2 + 7x +2
6x + 7x + 2 +2
(13x + 4)
2007-01-15 02:09:04 · answer #6 · answered by zachary hunt 2 · 0⤊ 1⤋
=6x^2+7x+2 6x^2 x 2=12x^2,12x^2=3x X 4x
=6x^2+3x+4x+2
=3x(2x+1)+2(2x+1)
taking 2 as common
=(2x+1)(3x+2) is the ANS
verification:-
(2x+1)(3x+2)=6x^2+7x+2
LHS:-
6x^2+4x+3x+2
=6x^2+7x+2
LHS=RHS
hence proved
2007-01-15 02:44:01 · answer #7 · answered by srinu710 4 · 0⤊ 0⤋
6x² + 7x + 2
6x² + 3x + 4x + 2
3x(2x + 1) + 2(2x + 1)
(2x + 2)(2x + 1)
- - - - - -s-
2007-01-15 02:26:03 · answer #8 · answered by SAMUEL D 7 · 0⤊ 0⤋
=6x^2+3x+4x+2
=3x[2x+1]+2[2x+1]
=[3x+2][2x+ 1]
2007-01-15 02:11:47 · answer #9 · answered by openpsychy 6 · 0⤊ 0⤋
(2x+1)(3x+2)
2007-01-15 02:10:21 · answer #10 · answered by Anonymous · 0⤊ 0⤋