6x^2 + 15x - 2x - 5
=6x^2 + 13x - 5
2007-01-15 01:11:52
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answer #1
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answered by Anonymous
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(3x-1)(2x+5) First multiply 3x by (2x+5)
(3x x 2x) +(3x x +5)
=6x^2+15x No.1
(-1 x 2x) + (-1 x +5) Then multiply -1 by (2x+5)
=-2x-5 No.2
6x^2+15x + -2x-5 Then add No.1 and No.2 together
=6x^2 +13x-5 Simplified
2007-01-15 01:17:03
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answer #2
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answered by S 1
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you have to multiply both parts in the left bracket with both parts in the right bracket
so 3x X 2x= 6x^2
3x X 5= 15x
-1 X 2x= -2x
-1 X 5= -5
then add them together
6x^2 +15x -2x -5=0
then simplify
6x^2 +13x -5=0
2007-01-15 01:15:47
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answer #3
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answered by Just me 5
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Difference of 2 Squares
(3x * 2x) + (3x * 5) + (-1 * 2x) + (-1 * 5) Simplify by Multiplication
6x^2 +15x + (-2x) + (-5) Simplify by addition
6x^2 + 13x - 5
2007-01-15 01:13:43
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answer #4
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answered by Chris D 1
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(3x - 1)(2x + 5) = 6x² - 2x + 15x - 5 = 6x² + 13x - 5
The answer is 6x² + 13x - 5
- - - - - -s-
2007-01-15 01:47:48
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answer #5
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answered by SAMUEL D 7
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=6x^2+13x-5
2007-01-15 01:44:00
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answer #6
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answered by openpsychy 6
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6x^2+13x-5
2007-01-15 02:47:40
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answer #7
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answered by Anonymous
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6x^2+13x-5
2007-01-15 01:12:25
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answer #8
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answered by raj 7
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6x^2+15x-2x-5
=6x^2+13x-5
its easy..
2007-01-15 01:49:53
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answer #9
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answered by saints fan 3
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6X^2+13X-5
2007-01-15 01:18:49
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answer #10
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answered by mrjomorisin 4
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