A model rocket is launched straight upward with an initial speed of 59.3 m/s. It accelerates with a constant upward acceleration of 1.61 m's^2 until the engines stop at an altitude of 207.4 m. What is the maximum height reached by the rocket?
2007-01-15 00:17:37 · 2 answers · asked by krstilyzed 1 in Science & Mathematics ➔ Physics
Assuming 'g' to be constant = 9.81m/s²
u = 59.3 m/s
a = 1.61 m/s²
s = 207.4 m
By the third equation of Kinematics:
v² = u² + 2*a*s
v² = (59.3)² + 2*1.61*207.4
v² = 3516.49 + 667.828
v² = 4184.318
v = 64.686 m/s
Velocity of the rocket at altitude of 207.4 m is 64.686 m/s
a = -g = -9.81 m/s² (acting downwards)
u = 64.686 m/s
v = 0 m/s
v² = u² + 2*a*s
0 = 64.686² - 2*9.81*s
19.62*s = 4184.318
s = 213.3 m
MAXIMUM height reached by the rocket from the GROUND LEVEL = 213.3 + 207.4 = 420.7 m
2007-01-15 00:28:40 · answer #1 · answered by Som™ 6 · 0⤊ 0⤋
Ask your teacher
2007-01-15 08:25:06 · answer #2 · answered by Anonymous · 0⤊ 1⤋