2007-01-15 00:01:40 · 5 answers · asked by ron p 1 in Science & Mathematics ➔ Mathematics
sqrt ((-6-2)² + (-1-5)²) = sqr(64 + 36) = sqr(100) = 10
2007-01-15 00:06:17 · answer #1 · answered by anton3s 3 · 0⤊ 0⤋
Change in y = -1 - 5 = -6
Change in x = -6 - 2 = -8
Total change = â[(-8)² + (-6)²]
= â[64 + 36]
= â100
= 10 units
2007-01-15 08:08:47 · answer #2 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋
use the formula: sq. root of (x-X)^2 +(y-Y)^2
= root (-6-2)^2 +(-1-5)^2
=root -8^2 +-6^2
=root 64+36
=root 100
=10
2007-01-15 08:45:51 · answer #3 · answered by Just me 5 · 0⤊ 0⤋
d=sqrt( (2+6)^2+(5+1)^2) =sqrt(100) =10
2007-01-15 08:11:16 · answer #4 · answered by santmann2002 7 · 0⤊ 0⤋
if two pts are (x1,y1),(x2,y2) then their is given by
d = [(x2-x1)^2 +(y2-y1)^2] ^ .5
so, let x1 = 2, x2 = -6 , y1= 5 & y2= -1
therefore , d = [(-6-2)^2 +(-1-5)^2] ^ .5
= [(-8)^2 +(-6)^2] ^ .5
= [64 +36] ^ .5 = 100 ^ .5 = 10 units
2007-01-15 08:11:22 · answer #5 · answered by Anonymous · 0⤊ 0⤋