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2007-01-11 03:41:39 · 7 answers · asked by CHRIS G 1 in Science & Mathematics Engineering

7 answers

xc capacitance is 1/ 2 pie fc

xc leads remember

f=frequency
c=capacitance

XL= 2pie fl

l=inductance which lags

this should give you the answer youre looking for. Another equation you may find useful is z=r squared +xl-xc

z=total impedance
r=resistance
xl=inductance
xc=capacitance

Something you may later go on to do with xc and xl

2007-01-11 05:00:21 · answer #1 · answered by Anonymous · 0 0

Xc is usually the abbreviation for capacitive reactance.

Xc = 1 / (2 x PI x f x C)

2007-01-11 11:49:45 · answer #2 · answered by efes_haze 5 · 1 0

Its Capacitive Reactance. Reactance is denoted by the symbol X and is measured in ohms.
If X > 0, the reactance is said to be inductive.
If X = 0, then the circuit is purely resistive, i.e. it has no reactance.
If X < 0, it is said to be capacitive.
Xc=1/wC=1/2pifc
where XC is the capacitive reactance measured in ohms
ω is the angular frequency, measured in radians per second
f is the frequency, measured in hertz
C is the capacitance, measured in farads

2007-01-12 17:46:23 · answer #3 · answered by Anonymous · 0 0

Xc = 1 / Cω = 1 / C x 2 x π x f
ω = 2 x π x f

where,
Xc - is the capacitive reactance measured in ohms
ω - is the angular frequency, measured in radians per second
f - is the frequency, measured in hertz
C - is the capacitance, measured in farrads

2007-01-11 14:49:50 · answer #4 · answered by Tarra 1 · 0 0

Xc = 1 / (2 ¶ f C) where :-
f = frequency in hertz
C = capacitance in farads
¶ = 3.14

2007-01-11 14:55:00 · answer #5 · answered by Como 7 · 0 0

i assume you mean reactance (resistance) of a capacitor?
if so 1/(2*PI*f*c)

PI = PI
f = frequency
c = value of capacitor in farads ie 1nf = 1*10^-9

2007-01-12 15:23:57 · answer #6 · answered by Anonymous · 1 0

ask the xmen

2007-01-11 14:01:30 · answer #7 · answered by Quentin G 2 · 0 1

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