Youneed to define a couple of things better to get your question answered correctly. One of these is whether the system is connected in a WYE or DELTA configuration, and the other is whether it is a SINGLE or MULTIPLE phase connection.
Assuming you have a three-phase, wye connection:
(Line Current in amperes) * (Line Voltage in volts) = (Power in Volt-amperes)
(Power in watts) = (Power in volt-amperes) * (power factor)
Therefore,
(Amps) = (Watts) / (power factor) / (volts)
2007-01-11 05:48:41
·
answer #1
·
answered by CanTexan 6
·
0⤊
1⤋
I=kW*1000/(V*pf)
or to put another way calculate VA = (kW*1000)/pf
then divide by V.
eg 1kw machine with 0.75 pf
=1333.3 VA
divide by 230V
=5.8A
if three phase 400V line then exactly the same as above but divide by 3 at the end ie 1.76A
2007-01-13 15:11:29
·
answer #2
·
answered by Mark G 2
·
0⤊
0⤋
P = I x E x PF (x Sq Root of 3 (if 3phase))
P = KW (Power)
I = Current
E = Voltage
PF = Power Factor
Sq Root of 3 = Factor to allow for 3 phase power (Leave out if single phase)
I = P / E x PF x Sq Root of 3
2007-01-11 17:13:13
·
answer #3
·
answered by ssn591exnuke 3
·
0⤊
1⤋
V*I=VA*pf =W so W/V=I... A 3kVA load with a pf of 0.9 supplied by 240v 50Hz = 3000*0.9=2.7kW therefore the current is 2700/240=11A. Note if the known rating is in kW you don't need the pf.
2007-01-12 17:57:33
·
answer #4
·
answered by Anonymous
·
0⤊
0⤋
Amps X Volts = Watts or
Amps = watts/volts
2007-01-11 11:44:41
·
answer #5
·
answered by Davy Crockett 3
·
0⤊
1⤋
Power (kW) = Voltage (V) x Amps (I), so
Amps (I) = Power (kW) / Voltage (V)
2007-01-11 14:39:12
·
answer #6
·
answered by Tarra 1
·
0⤊
1⤋