2007-01-10 10:44:43 · 7 answers · asked by tifiny g 1 in Science & Mathematics ➔ Engineering
3=7(k-4)
3=7k-28
31=7k
k=4.43...
2007-01-10 10:56:25 · answer #1 · answered by Anonymous · 0⤊ 0⤋
3 = 7(k-4)
k-4 = 3/7
k = 3/7 +4
2007-01-10 12:59:41 · answer #2 · answered by Ivy 3 · 0⤊ 0⤋
3=7(k-4)
3= 7k-7x4
3=7k-28
+28 +28
31=7k
31/7
k= 4 3/7
or
k= 31/7
2007-01-10 10:56:53 · answer #3 · answered by A F 1 · 0⤊ 0⤋
3 = 7k - 28
3 + 28 =7k
31 = 7k
31/7 =k
2007-01-10 10:59:52 · answer #4 · answered by sg 2 · 0⤊ 0⤋
k = (30/7)+4
k= 4.42857143
2007-01-10 12:14:16 · answer #5 · answered by komatsu 2 · 0⤊ 0⤋
k= 31/7
At least all the answers agree on this one..that is rare.
2007-01-10 15:49:48 · answer #6 · answered by Chris W 2 · 0⤊ 0⤋
k=31/7
or
k=4.4285714285714285714285714285714
2007-01-10 10:54:47 · answer #7 · answered by sweet1211pea 1 · 0⤊ 0⤋