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Assuming a 60 hz system, how much time in seconds is the maximum positive current behind the maximum positive voltage when the current lags the voltage by;

a) 90 degrees
b) 0 degree
c) 60 degrees

2007-01-09 16:22:09 · 8 answers · asked by Teolo B 1 in Science & Mathematics Engineering

8 answers

I could be wrong, but from a logical deduction this is what I think:

If it is a 60 hz system that means that the it takes 1/60 seconds to complete one full period. Assuming that it's some sort of sine or cosine wave, I would say:

(a) 90 degrees is 1/4 of 360 degrees (one period). So the time lag is (1/60)*(1/4) = 1/240 seconds

(b) 0 degrees would be 0 time lag.

(c) 60 is 1/6 of 360 so (1/60)*(1/6) = 1/360 seconds

Of course, I've never seen this specific type of problem, but logically I would think this is the answer?

2007-01-09 16:36:04 · answer #1 · answered by Anonymous · 1 1

Time period of each cycle = 1/60 of a second

a) for 90 degrees, the gap should be 1/4th of time period = 1/240
b) No time lag
c) for 60 degrees, the gap should be 1/4th of time period = 1/360

2007-01-09 19:04:20 · answer #2 · answered by Anonymous · 0 0

90 im not sure which one is first but im pretty sure voltage leads current by 90degrees.

whatever Hz, i there is always a 90deg difference between the two. correct me if im wrong.

2007-01-09 16:27:19 · answer #3 · answered by lnfrared Loaf 6 · 0 0

6ec6ab4bba8042d2be7f45e3ff621a7onsider: Z = (XL-XC)/R + j6ec6ab4bba8042d2be7f45e3ff621a76ec6ab4bba8042d2be7f45e3ff621a76ec6ab4bba8042d2be7f45e3ff621a7 -6ec6ab4bba8042d2be7f45e3ff621a76ec6ab4bba8042d2be7f45e3ff621a76ec6ab4bba8042d2be7f45e3ff621a7 6ec6ab4bba8042d2be7f45e3ff621a7hase = atan[6ec6ab4bba8042d2be7f45e3ff621a76ec6ab4bba8042d2be7f45e3ff621a76ec6ab4bba8042d2be7f45e3ff621a7-6ec6ab4bba8042d2be7f45e3ff621a76ec6ab4bba8042d2be7f45e3ff621a76ec6ab4bba8042d2be7f45e3ff621a76ec6ab4bba8042d2be7f45e3ff621a76ec6ab4bba8042d2be7f45e3ff621a7] if 6ec6ab4bba8042d2be7f45e3ff621a76ec6ab4bba8042d2be7f45e3ff621a7 > 6ec6ab4bba8042d2be7f45e3ff621a76ec6ab4bba8042d2be7f45e3ff621a7 then section approaches +ninety tiers as (XL-XC)/R is going to 0 if 6ec6ab4bba8042d2be7f45e3ff621a76ec6ab4bba8042d2be7f45e3ff621a7 < 6ec6ab4bba8042d2be7f45e3ff621a76ec6ab4bba8042d2be7f45e3ff621a7 then section approaches -ninety degress as (XL-XC)/R is going to 0 if (XL-XC)/R = 0 then the section is the two -ninety tiers or +ninety tiers the question as reported has no meaning.

2016-10-30 12:08:36 · answer #4 · answered by santolucito 4 · 0 0

a) 1/240 th of a second, or 0.00416667 seconds
b) zero seconds
c) 1/360 th of a second, or 0.0027778 seconds

Now check my working.

2007-01-09 16:38:26 · answer #5 · answered by expie 4 · 1 1

ahh i remember learning about that crap back in the day. i think i still have all the solution manuals somewhere...

2007-01-09 16:27:19 · answer #6 · answered by mdigitale 7 · 1 0

If you don't answer the question you will get it wrong.
If you divide by 36000 you might still get it wrong.

2007-01-09 16:35:37 · answer #7 · answered by Happy Camper 5 · 0 1

im guessin b. cuz it always is, but dont trust me cuz i dont know it that well

2007-01-09 16:27:08 · answer #8 · answered by Anonymous · 0 1

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