how long would it take a human being to fall from 32000 feet in the air to the ground from an airplane?

Answer 1

I takes a human body (170-lbs. average) 14 seconds to attain "terminal velocity" (maximum speed), which is 176 ft./sec or approx. 120 mph. The distance covered in that first 14 seconds is approximately 1800 ft. From there, the person continues to fall at 176 ft./sec over the remaining 30,200 feet, which would take another 2 minutes and 52 seconds.

Total time (approximated) would be 3 minutes 6 seconds.

Answer 2

Real fast and the stop would be real fast. So if you fall out of a airplane at 32000 feet and u don't have some good reason for doing so let me tell u the answer. Don't fall out of a airplane/That would be just Dumb. U wont have a real ideal how fast one second can last my be a life time in ones reality so using math can give you a answer 32 feet per sec.Butt tell that to the one falling.

Answer 3

I agree with Devilish. All the physics work fine in a vacuum but the bottom line is a body will reach a terminal velocity in the atmosphere. My figures work out to about 3 minutes but there are variables to consider. Air currents and up or down drafts can alter the equation but body position may be the biggest. If the person falling has assumed a frog position, chest down with arms and legs extended like a sky diver the time can be increased slightly. And likewise, if they assume a dart position, head down, hands at there sides and feet slightly spread they can achieve speeds well above 120 mph thus shaving time off of the fall.

Hope that answers your question and thumbs up to Devilish, he lives in the real world...

Answer 4

1 feet = 0.3048 m, so the vertical distance of free fall = 32000 ft. x 0..3048 m/ft.
= 9753.6 m

Using the following equation of motion of the body,

we have s = u*t + (1/2)*g*t*t

where s = vertical distance covered = 9753.6 m

u = initial velocity (assuming 0 m /s i.e: rest)

t = total time taken by the object to drop to the surface (unknown)

g = acceleration due to gravity = 9.81 m/s (on earth)

feeding this given data into the above equation and neglecting frictional resistance due to air, we get:

t = 44.592 seconds

Hence the total time taken by the human being to fall from 32000 feet in the air to the ground from an aeroplane is 44.592.
(In a real life situation the airplane has a velocity of its own and that has to be taken into consideration, but I assumed rest to make the solution simple).

Answer 5

The acceleration of gravity is 32 feet per second squared. That means after 1 second you will be falling 32 FPS, after 2 seconds 128 FPS (32x2x2), after 3 seconds 288 FPS (32x3x3), etc.

I believe it takes between 14 and 15 seconds to fall 32,000 feet but in reality the air resistance might make that more (much more if you've deployed a parachute).

Answer 6

Speed increses by 1 meter per second every 0.1 seconds. Which is an increase of 10 m/s. The accerleration of a free falling object is a constant value of 10 m/s. Note that this value varies with latitude. The value is 9.81 m/s squared at the Earth's poles and 9.78 m/s squared at the equator.

Answer 7

There are too many factors to be accurate. Gravity works at (can't swear to this but I think this is right) 32 ft. per second, squared.

Answer 8

32 ft per sec per sec

Answer 9

Why do you want to know this?

1-800-suicide

Answer 10

he would fall at 32 feet per second per second. Do the math.