there is a girl i still love and after almost 3 years we still talk but we broke up beccause of number of reasons but we both still desire to be with each other and I know I want to be with her but on the other hand how do I know she really wants to be with me even though she tells me she does......
2007-01-09 11:48:19 · 6 answers · asked by Anonymous in Family & Relationships ➔ Singles & Dating
You have to trust her , if there is no trust in the relationship then how can either one of you be truly happy?
Talk to her and tell her you want to make sure this is what she wants because you really love her and don't want to get hurt again.Just talk to her express your feelings women love that in a man.
GOOD LUCK
2007-01-09 11:56:02 · answer #1 · answered by " Dixieland Delight " 3 · 0⤊ 0⤋
I think what you need to do is think about why you broke up first. Then think wether those reasons are still there or not. She says she wants to be with you and that may be true but if the reasons you broke up are still there then you will only break up again. If you feel that you still canb not be togethjer because of those reasons do not get back together and spare both of you the pain of breaking up again
2007-01-09 20:00:05 · answer #2 · answered by melthule 3 · 0⤊ 0⤋
true if shes talking to you then take it to the next level but if you broke up for numbers of reasons ..you may want to move on and try new people
2007-01-09 19:54:07 · answer #3 · answered by Molly 2 · 0⤊ 0⤋
The only thing left to do is start your relationship up again. Life is too short to let good things go. Let whatever is going to happen happen.
2007-01-09 19:54:30 · answer #4 · answered by rubyred 4 · 0⤊ 0⤋
You don't know. But if she's still speaking to you, then it means something.
Stop thinking so much about it.
2007-01-09 19:51:57 · answer #5 · answered by Anonymous · 1⤊ 0⤋
You know she cares about you if she is willing to give you something she values (money, her car, her body as the host of your first born...).
2007-01-09 19:54:56 · answer #6 · answered by Tammy27 2 · 0⤊ 0⤋