2007-01-08 22:55:44 · 6 answers · asked by amanda p 1 in Science & Mathematics ➔ Engineering
no capacitor in series ct =1/c1+1/c2+1/c3 were as in paraell ct =c1+c2+c3. In series for resistors rt=r1+r2+r3 and parallell rt=1/r1+1/r2+1/r3
2007-01-08 23:16:27 · answer #1 · answered by Anonymous · 0⤊ 0⤋
No, capacitors add up in exactly the opposite way from resistors. In series Rtotal = R1 + R2 + R3 but 1/Ctotal = 1/C1 + 1/C2 + 1/C3. Conversely, in parallel, Capacitors just add up Ctot = C1 + C2 + C3 but resistors are added inversely.
2007-01-09 07:01:23 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Capacitors function in an opposite way to resistors. While resistors in series add up to make an equal resistor, for capacitors in series the inverse capacities add up for the inverse of an equal capacity (just like parallel resistors). Parallel capacitors function like resistors in series.
2007-01-09 07:01:02 · answer #3 · answered by supersonic332003 7 · 1⤊ 0⤋
No! Capacitors in series have similar characteristics to resistors in parallel.
2007-01-09 07:00:19 · answer #4 · answered by OOHAY 2 · 0⤊ 0⤋
I'm not totally sure but I don't think so. Capacitors store electricity and give a burst when needed. Resistors resist the flow of current, therefore slowing it down. So I'd say not.
2007-01-09 07:01:19 · answer #5 · answered by capnemo 5 · 0⤊ 0⤋
If you are talking about impedance, yes, but if you are talking about equivalent capacitance, then capacitors in series behave like resistors in parallel, i.e.
1/C = 1/c1 + 1/c2 + 1/c3 + .....
2007-01-09 07:05:12 · answer #6 · answered by Helmut 7 · 0⤊ 0⤋