2007-01-08 04:50:10 · 13 answers · asked by larrythelamb 2 in Politics & Government ➔ Law Enforcement & Police
why u wanna try and do some crime?or bust into the police station?either way I dont think u wanna know for legal reasons
2007-01-08 04:52:23 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Are you planning on doing something naughty just at shift change? Give you an extra few minutes get away time...as long as it's not rush hour because Reading is at a standstill around the Police Station, IDR and Oracle area between 1600 and 1830hrs... best be on skates....
2007-01-08 05:39:58 · answer #2 · answered by reggie 4 · 0⤊ 0⤋
Ask them in the police station. You might find out a lot faster than you think. Why do you want to know?.
2007-01-09 05:32:03 · answer #3 · answered by greagues2 2 · 0⤊ 0⤋
a great form of the police vehicles are automatics so the trend may be PRNDL. If the automobile is instruction manual that's in all hazard in the H trend with opposite up an dto the left, above first. sorry could no longer help it. can enable you comprehend approximately paintings shift varieties in a great form of the U. S. yet no longer Britain.
2016-11-27 20:00:45 · answer #4 · answered by krausz 4 · 0⤊ 0⤋
Ask Morse. But seriously what an extraordinary question. How about asking the police in Reading itself?
2007-01-08 05:00:33 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I think its stripped with a few red and yellow dots. Quite a pretty pattern actually
2007-01-08 04:58:03 · answer #6 · answered by Anonymous · 0⤊ 0⤋
It changes daily
2007-01-08 18:48:05 · answer #7 · answered by Hawkeye77 2 · 0⤊ 0⤋
What an extreamley dubious question
2007-01-08 04:54:04 · answer #8 · answered by Spooky Mouse 5 · 0⤊ 0⤋
WHY ARE YOU THINKING OF DOING A BIG BLAG.....ASK YOURSELF IF YOU ARE TRYING TO FIND OUT ON HERE GIVE UP ..AND DONT FORGET YOUR DOLE CARD WHEN YOU SIGN ON
2007-01-08 04:53:45 · answer #9 · answered by michael b 5 · 0⤊ 0⤋
If you want to know the time .... ask a policeman!
2007-01-08 05:02:02 · answer #10 · answered by dave a 5 · 0⤊ 0⤋