I am removing a portion of a load bearing wall in my single story home.
2007-01-08 03:11:43 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
well dude you are missing one key element. the weight per foot of the beam. Not enough information to adequately answer the question. I'm curious where this 410lbs/ft figure came from. But if you are sure of your distributed load you should be able to go to a steel manuel and it will tell you what size beam will work. Or better yet consult a local structural engineer, I know it's more money but peace of mind is priceless, especially if you have children in the house.
2007-01-08 03:19:32 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The exterior dimensions of an I-beam are only part of the required information. In order to answer your question, one also needs to know the thickness of the flanges and the web.
Of the W6's I am familiar, the load seems too heavy for that span. Again, you may not have a W6, you might have another type of I-beam.
On related notes: if you are removing a load bearing wall with that kind of loading, do yourself a favor and hire a professional engineer. This is not a trivial instance. If you misjudge this, your house will suffer serious damage. Second, if you have a single-storey home, what is the wall holding up that weighs that much? That is a pretty hefty roof load unless you have a VERY large tributory area.
2007-01-08 14:32:35 · answer #2 · answered by Imagineer 3 · 0⤊ 0⤋
What specific beam section are you refering to. I see no typical 6x6 W or S sections for steel beams. If you are talking a 6 x 6 timber, then by inspection, no, it won't support that much load.
For a distributed load, M = wl^2/8
Your moment is 88,560 lb * in, = M.
Fb = Allowable Bending Stress, psi. This depends on wood species.
S = Section Modulus = bd^2/6 in^3 for a rectangular beam section.
You will also need to check deflection. Shear should be OK.
Sreq. = M/Fb This is unfactored. The load factor depends on the type of load.
2007-01-08 13:17:20 · answer #3 · answered by daedgewood 4 · 0⤊ 0⤋
A better description - the load I am supporting I have calculated (with help of an architech freind) to be 410 lbs per linear foot spanned.
2007-01-08 11:55:11 · answer #4 · answered by robin y 1 · 0⤊ 0⤋