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since gravitational force varies with latitude, and hence so does the weight,due to greater distances at the equator, than at the poles,
and hence so do the weights of objects at the surface of the earth at different latitudes due to varying distances from the earths center ,when weighing or calibrating scales or balances at different latitudes, is there a correction applied, so that there is no difference in the weights measured,on an international basis for weighing bulk commodities, assuming weights used for measuring and weighingare SI units of metre ,kilogramme and sec

2007-01-05 20:20:42 · 4 answers · asked by kurien_rockypkr 1 in Science & Mathematics Engineering

4 answers

You use nominal weights calibrated against a standard which is agreed upon internationally and kept under certain conditions in a specified place. This is what is called the standard weight used all around the globe. However technically speaking the actual weight varies with latitude and altitude.

2007-01-06 03:18:25 · answer #1 · answered by Mesab123 6 · 0 0

Mass vs Weight topic has been discussed by a number of organizations including ASME, Canadian Metric Association and ISO ( system Internaional ) etc.

We continue to use the term weight for signifying what we are buying in terms of mass from the times that the two pans of the balance are equally affected by gravity, no matter where you take it.

To measure wieght, one must utilize a spring scale - which will indeed give you a different number for the same quantity measured on earth or moon.

2007-01-08 05:25:22 · answer #2 · answered by Anonymous · 0 0

Regardless of the measurement system, you use certified test weights or masses. Although the weights of masses change with altitude, they are the same relative to eachother.

That is, two 100 N weights will weigh the same as each other regardless of altitude.

2007-01-05 22:23:44 · answer #3 · answered by gebobs 6 · 1 0

the max. and min. weight of anything with a mass =(m) on the earth is between 9.78*m and 9.82*m

2016-05-22 22:22:54 · answer #4 · answered by Anonymous · 0 0

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