3 guys go to a hotel. The hotel room cost $30. They each pay $10 and share one room. After the 3 men left the front desk, the manager just remembered that today is the special and the room is actually $25. So the manager gives $5 to the Bellboy to return to the 3 men.
As the Bellboy was walking to the room he realized that the 3 men cannot evenly split $5 without change. So he gave the men $3 and HE pocketed $2. So now the 3 men each received $1 back each. So in other words they paid $9 each for the room.
$9 x 3 (the 3 men) = $27 + $2 (the $2 the bellboy pocketed) = $29
Where is the missing dollar?
2007-01-05 10:52:21 · 6 answers · asked by talofa lava 2 in Entertainment & Music ➔ Jokes & Riddles
The answer is the equation is wrong. You can't add what the men paid to what the bellboy kept and make sense... cents? get it. (groan). You can however add what everyone has:
$25 (manager) + $2 (bellboy) + $3 ($1 each visitor) = $30.
2007-01-05 11:06:53 · answer #1 · answered by volleyjacket 3 · 0⤊ 0⤋
Mathamatical error in calculation. the five dollars is a refund so you would have to subtract the $2 from the bellboy and not add it to get $25, or you would have to add the $3 and not subtract it to get $30.
2007-01-05 19:07:01 · answer #2 · answered by K G 2 · 0⤊ 0⤋
its isn't $29 it is actually 30 watch
30-25= 5
2+3=5
5+25= 30
so instead of multiplying by 3 you should add the 2 dollars to the 3 dollars a then add to the 25 it will equal 30
so inessense they each paid 25/3= roughly $8.33 apeice
2007-01-05 19:41:49 · answer #3 · answered by Garnet 1 · 1⤊ 0⤋
it went to the bellboy as a tip
2007-01-05 18:57:09 · answer #4 · answered by gymnst1012 1 · 0⤊ 0⤋
The manager has it.
2007-01-05 18:55:57 · answer #5 · answered by rekcut94 1 · 0⤊ 0⤋
DUH!!!! the robber staying in room 28 stole it!!!!!
2007-01-05 18:58:49 · answer #6 · answered by Anonymous · 0⤊ 0⤋