2007-01-05 05:15:52 · 5 answers · asked by damian a 1 in Science & Mathematics ➔ Engineering
the input voltage is 10V, R1 and R2 are in series and R display is paralel with R2
2007-01-05 05:29:05 · update #1
since both resistors have same size and are in row you'll have half of the voltage on each resistor.
2007-01-05 05:41:01 · answer #1 · answered by blondnirvana 5 · 0⤊ 1⤋
Since R1 = R2 = 100 ohms, the voltage across R2 is 1/2 the voltage across R1 and R2 in series.
2007-01-05 13:26:09 · answer #2 · answered by ironduke8159 7 · 0⤊ 1⤋
r1 and r2 are in series.
let r3 be resistance of display.
r3 and r2 are in parallel.
Let R be equivalent resistance of r2 and r3
Thus 1/R =1/r2 + 1/r3
1/R = 1/100 + 1/200
1/R = 2/200 + 1/200 = 3/200
R=200/3 ohms
Total resistance of circuit = 100 + 200/3 ohms
=500/3 ohms
Total current =10/500/3 = 3/50A
Voltage across series resistor = 3/50 x100V=6V
Voltage across parallel resistors is then 4V
2007-01-07 06:26:26 · answer #3 · answered by Como 7 · 0⤊ 0⤋
R2 and R display are in parallel and R2 is 100 and R display is 200 ohms so their parallel resistance is 66.66 ohms. Assuming that the display and R2 are the part that goes to ground, the voltage across them is (66.66/166.66) * 10 volts ... You can do the arithmetic.
2007-01-05 13:21:17 · answer #4 · answered by Gene 7 · 1⤊ 0⤋
About 4V. Eugene's answer is correct.
(My first time on here.... what is this? homework help line or something?)
2007-01-05 15:00:53 · answer #5 · answered by Yen P 1 · 0⤊ 0⤋