based on the farad value of the capacitor
2007-01-04 09:39:10 · 5 answers · asked by macgyver 1 in Science & Mathematics ➔ Engineering
can it be based on the farad vlue of the capacitor (i think specific values of capacitance will hold a scpecific number of volts)
2007-01-04 12:18:22 · update #1
You divide the charge by the farad value.
2007-01-04 09:42:46 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Capacitors are rated in farads and voltage. You can only charge to up to the rated voltage, anymore and it would self destruct. The micro farads is a value of the CEMF when it is discharged. With no resistance it would be nearly instantaneous. With resistance it could take days. In open air it could last for days. Power supplies use caps to smooth out the VDC ripple after rectification. The current is done by inductors or what is called a choke
2007-01-04 22:50:14 · answer #2 · answered by btlcrzr 2 · 0⤊ 0⤋
Use this formula: Q = C * V
So, Volts = charge divided by capacitance.
Be sure to keep consistent units. Use volts for voltage, coulombs for charge, and farads for capacitance.
2007-01-04 19:37:24 · answer #3 · answered by vrrJT3 6 · 0⤊ 0⤋
take the amount of coulombs, then divide it by the number of farads
2007-01-04 17:47:54 · answer #4 · answered by The Ponderer 3 · 0⤊ 0⤋
v=I*r, so Voltage = Current * resistance.
2007-01-04 17:46:40 · answer #5 · answered by Sean 5 · 0⤊ 0⤋