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x+5 + 2x-1 (2x is on the bottom of x+5, and 4x is on the bottom of 2x-1. In other words, they are the denomenators)

These are suppose to be treated as if they are fractions,
by finding the largest common denomenator,
and then cross multipication, reducing and all of that. Still, either
my algebraic math is wrong, or something
else is wrong. Please help me solve this monster. Thank you very much.

2007-01-03 12:29:49 · 19 answers · asked by Alina 2 in Science & Mathematics Engineering

19 answers

If the problem is set up this way:

x+5 + 2x-1
------ ------- = 0
2x 4x

Multiply the first half of the problem by 2 over 2 so that your denominator for both sides is 4x. Then you can simplify the problem so you get:
2x + 10 + 2x -1
---------------------- = 0
4x

Multiply both sides by four and simplify

you get 4x +9 =0

subtract by 9 and divide by 4 your answer is:

x = -9/4

2007-01-03 12:36:54 · answer #1 · answered by N :O) 3 · 0 0

Just substitute a number for the "x"..as 10......no matter what number you use the answer is 1 & 9/40th

(x+5)/2x + (2x-1)/4x

(10+5) / (2 x 10) + [ (2 x 10) - 1] / (4 x 10)

15 / 20 + (20 - 1) / 40

3/4 + 19/40

30/40 + 19/40

= 49/40 or 1 & 9/40 th

2007-01-03 12:52:31 · answer #2 · answered by TEABERRYEAGLE 1 · 0 0

Rewriting your problem:

[(x+5) / 2x] + [(2x-1) / 4x]

First, you find the common denominator, which happens to be 4x. In order to create this common denominator with the left side fraction, we will multiply the entire fraction by 2/2, a value of 1. We get:

[(2(x+5)) / 2(2x)] + [(2x-1) / 4x]
Simplified:
[(2x+10) / 4x] + [(2x-1) / 4x]

Next, we can combine the fractions with the new common denominators. We get:

(2x+10+2x-1) / 4x

Now, we can add like terms and simplify:

(4x+9) / 4x

Voila.

Edit: Realized the possible misinterpretation. Follow Nonny :O) for solving the equation when set equal to zero. My answer is merely a simplification of your equation, as I did not see an "= 0" at the end of your question.

2007-01-03 12:37:55 · answer #3 · answered by Jon 1 · 2 0

This is actually quite simple.

x+5/2x +2x-1/4x right?

multiply x+5/2x by 2/2...this is just 1 so it changes nothing, right?

now you have 2x + 10/4 x + 2x - 1/4x

Now simply add...= 4x + 9 or 2x +2x +10 - 1...right?

Answer 4X + 9 all over 4

If you want to check the work, assign a value to x...eg 2 and do the math.

the answer is 17/8 before and after the reduction.

There is no cross-multiplication required.

2007-01-03 12:48:42 · answer #4 · answered by Ralph the Sage 2 · 1 0

so ure saying that x+5 over 2x =
2x= x+x so cancel an x from the top n bottom and left with 5over x- u could argue that x=1 so therefore largest answer =5

2x-1 over 4x= x+x-1 over x+x+x+x so cancel two x's from top and bottom and left with -1 over 2x

if you have to plus these then 5 over x +-1 over 2x
=5/x + -1/2x

cross multiply for the top denomenators and multiply the bottom two for the bottom numbers

so 10x (5 x 2x) /2x squared +-1x / 2x squared

so now bottom one can be generalise to 2x squared and on top have 10x+ -1x /2xsquared

cancel one x from each so

10+ -1/ 2x

so 9/ 2x and and then reduce to 4.5x

i think...
hope this has helped but i did maths 5 yrs ago- vaguely remember it- hey but i got an A! :) so hope it works...

2007-01-03 12:42:37 · answer #5 · answered by Anonymous · 0 1

x+5 2x-1
____ + _____ = 0

2x 4x

multiply the left fraction by 2/2 and expand to get

(2x+10 +2x -1)/ 4x = 0

or (4x +9)/4x = 0

which gives 4x/4x + 9/4x = 0

or 1 + 9/(4x) = 0

or 9/(4x) = -1

x = -9/4

although. i think your instructor probably wants you to do this...

x+5 2x-1
____ + _____ = 0

2x 4x

gives

x+5 (2x-1)
____ = - _____
2x 4x


which is
x+5 -2x+1
____ = _____

2x 4x

cross multiplying gives

(4x) * ( x+5) = (2x) * (-2x + 1)

or

4x^2 + 20x = -4x^2 + 2x

so that

8x^2 + 18x = 0

dividing by x (assuming x is not equal to zero)

gives

8x + 18 = 0

so that

x = -18/8 = -9/4

2007-01-03 13:26:02 · answer #6 · answered by Dr W 7 · 0 0

You need an equals in there other wise you are simplifying and not solving the equation....
and if I understand you a better way of writing it could be:
((x + 5) / 2x) + ((2x - 1) / 4x)

2007-01-03 12:33:43 · answer #7 · answered by purplebuggy 5 · 1 0

[I'm assuming that the expression (x+5)/2x + (2x-1)/4x is equal to 0]

If this is the case,

(x+5)/2x + (2x-1)/4x = 0

2(x+5)/4x + (2x-1)/4x = 0

(2x+10)/4x + (2x-1)/4x = 0

(2x+10+2x-1)/4x = 0

Multiply throughout by 4x

2x+10+2x-1 = 0
4x + 9 = 0
x = -9/4 or -2.25

2007-01-03 13:27:34 · answer #8 · answered by The Alchemist 2 · 0 0

I assume the expression equals zero.
(x+5)/(2x) + (2x-1)/(4x) =0
shortcut (double top and bottom of first term for common denominator)
(2x+10)/(4x) + (2x-1)/(4x) = ((2x+10)+(2x-1))/(4x) =
(2x+2x+10-1)/(4x) =
(4x+9)/(4x)= ((4x)/(4x)) + (9 / (4x) =
1 + 9/(4x)
9/(4x) = -1
9/-1 = 4x
-9/4 = x
-2.25 = x (I think. It has been a long time! Can anyone check me?)

2007-01-03 13:06:32 · answer #9 · answered by J C 5 · 0 0

it is an strange undertaking. i've got been given x+9 over x. the conventional denominator i've got been given grew to become into 4x, so which you multiply each and every thing interior the 1st fraction via 2, so which you have 2x+10/4x+2x-9/4x. if iyou upload them mutually you get 4x+9/4x, decrease and that i think of you get x+9/x. stable success, it is tough!

2016-10-06 09:49:16 · answer #10 · answered by ? 4 · 0 0

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