You are at the top of a 600 meter televison tower and drop a hammer. For each of the first 7 seconds?

Answer 1

the velocity after the first sec=9.8m/sec
after the 2 nd sec=19.6 m/sec
and so on
if this is your question

Answer 2

Assuming that you want to know what I'm thinking during those first seven seconds the answer is this:

1. I can't believe I dropped my hammer.
2. Why did I park my car under the tower?
3. Should I climb back down and get my hammer...or just use my shoe?
4. If I climb back down to get my hammer...how difficult will it be to dislodge from my car?
5. What if I drop my shoe?
6. Hey! I can see my house!
7. I really shouldn't have eaten that chili dog for lunch.

Answer 3

Okay, let just assume this is one of those "ideal" circumstances with no friction and no wind resistance so we will not have to worry about the terminal velocity of the hammer.

As object dropped on or near the surface of the earth accelerates towards the earth at 9.8 m/s^2 (meters per second squared. Assuming you want the distance the hammer is displaced for each of the first 7 seconds you will need to multiply 9.8 times the number of seconds elapsed squared.

9.8 meters the first second.
32.9 meters after the second second.
88.2 meter after the third second.
156.8 meters after the fourth second.
245 meters after the fifth second.
352.8 meters after the sixth second.
480.2 meters after the seventh second.

Answer 4

What is your question?